Suppose that the Sun runs out of nuclear fuel and suddenly collapses to form a white dwarf star. The size shrinks and became as big as earth. Assuming that there is no loss in mass and it maintained to be a solid sphere, what would be the little white dwarf star's rotation period. The present rotation of the sun is about 25 days. Earth's radius = 6.37x10^6 Sun's radius = 6.96x10^8

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom
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Problem 14P: Two planets X and Y travel counterclockwise in circular orbits about a star as shown in Figure...
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Suppose that the Sun runs out of nuclear fuel and suddenly collapses to form a white dwarf
star. The size shrinks and became as big as earth. Assuming that there is no loss in mass and it
maintained to be a solid sphere, what would be the little white dwarf star's rotation
period. The present rotation of the sun is about 25 days.
Earth's radius = 6.37x10^6
Sun's radius = 6.96x10^8
Transcribed Image Text:Suppose that the Sun runs out of nuclear fuel and suddenly collapses to form a white dwarf star. The size shrinks and became as big as earth. Assuming that there is no loss in mass and it maintained to be a solid sphere, what would be the little white dwarf star's rotation period. The present rotation of the sun is about 25 days. Earth's radius = 6.37x10^6 Sun's radius = 6.96x10^8
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