sume a dieter drinks 2.3 kg (i.e., 2.3 L) of ice water every day. The specific heat of water is 4.186 × 103 J/(kg⋅°C). Part (a) How much energy, in joules, does the dieter’s body need to provide in order to warm the water over a full year. Take 365 days in a year. Part (b) One pound of fat supplies 3500 kcal (Cal) to the body, where 1 kcal (Cal) = 4.186 × 103 J. How much fat, in pounds, can the dieter hope to lose in a year by drinking ice water rather than water at body temperature?
sume a dieter drinks 2.3 kg (i.e., 2.3 L) of ice water every day. The specific heat of water is 4.186 × 103 J/(kg⋅°C). Part (a) How much energy, in joules, does the dieter’s body need to provide in order to warm the water over a full year. Take 365 days in a year. Part (b) One pound of fat supplies 3500 kcal (Cal) to the body, where 1 kcal (Cal) = 4.186 × 103 J. How much fat, in pounds, can the dieter hope to lose in a year by drinking ice water rather than water at body temperature?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter21: Heat And The First Law Of Thermodynamics
Section: Chapter Questions
Problem 71PQ
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One strategy when on a diet is to drink ice water. The body must burn calories to warm the water from 0°C to a body temperature of 37°C. Assume a dieter drinks 2.3 kg (i.e., 2.3 L) of ice water every day. The specific heat of water is 4.186 × 103 J/(kg⋅°C).
Part (a) How much energy, in joules, does the dieter’s body need to provide in order to warm the water over a full year. Take 365 days in a year.
Part (b) One pound of fat supplies 3500 kcal (Cal) to the body, where 1 kcal (Cal) = 4.186 × 103 J. How much fat, in pounds, can the dieter hope to lose in a year by drinking ice water rather than water at body temperature?
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