Step 3 Now write the derivative in terms of x by recalling that u = -3x + 7 and v = x + 7. du 1 += dx V [In(u)] + dx [In(v)] = dx 1 u 1 -3x + 7 d dx dv dx 1 d ] ) + ( x + 7) + (x + 7) X+7 dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Step 3
Now write the derivative in terms of x by recalling that u = -3x + 7 and v = x + 7.
1
d
dx
[In(v)]
V
-[In(u)] +
dx
=
=
1
u
du
dx
+
1
d
-3x + 7 dx
dv
dx
1
) + ( + + 7) = ² ( x + 7)
d
-(x
x
dx
Transcribed Image Text:Step 3 Now write the derivative in terms of x by recalling that u = -3x + 7 and v = x + 7. 1 d dx [In(v)] V -[In(u)] + dx = = 1 u du dx + 1 d -3x + 7 dx dv dx 1 ) + ( + + 7) = ² ( x + 7) d -(x x dx
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