Sprayer AR is 75L/ha , sprayer tank capacity is 90OLiter of spray mix , field dimensions 500m x 600m and pesticide rate is 5L/ha then answer the question below what is mix spray volume needed to cover the whole area 6950 liter 67500 liter 2750 liter 2250 liter

Sprayer AR is 75L/ha , sprayer tank capacity is 90OLiter of spray mix , field dimensions 500m x 600m and pesticide rate is 5L/ha then answer the question below what is mix spray volume needed to cover the whole area 6950 liter 67500 liter 2750 liter 2250 liter

Name: 7Sprayer AR is 75L/ha , sprayer tankcapacity is 90OLiter of spray mix
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Description: 7Sprayer AR is 75L/ha , sprayer tankcapacity is 90OLiter of spray mix , fielddimensions 500m x 600m and pesticiderate is 5L/ha then answer the questionbelowwhat is mix spray volume needed to coverthe whole area6950 liter67500 liter2750 liter2250 lit

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter2: The Kinetic Theory Of Gases

Section: Chapter Questions

Problem 33P: Calculate the depth to which Avogadro's number of table tennis balls would cover Earth. Each ball...

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Calculate the depth to which Avogadro's number of table tennis balls would cover Earth. Each ball has a diameter of 3.75 cm. Assume the space between balls adds an extra 25.0% to their volume and assume they are not crushed by their own weight.
2.6 times that developed in the aluminum: f, 2.6f, Because P AJ Apanhola + A,J. (2.6) (0.5) () + (0.5) () 5000, we have f. 2777 lb/in. and f- 7220 lb/in.¹ (The nA, value is often called a transformed area; the steel is considered to have been transformed into a modified area of aluminum that is structurally equivalent.) To find fal deformations, fa/B. 2777/11,300,000 0.000246 and AL, L-0.00245 in =/ft ANA QUESTIONS 2.1. A force of P defined by the angle 0,= 75° to the horizontal acts through a point. What are the components of this force on the x- and y-axes? [See Figure 2.59(Q1).] Questions. 211- L/2- 2.2. The components of a force on the x- and y-axes are 0.50P and 1.50P, respectively. What are the magnitude and direction of the force? [See Figure 2.59(Q2).J Answer: 1.58P at 0,= 71.5°. 2.3. The following three forces act concurrently through a point: a force P acting to the right at 0, 30° to the horizontal, a force P acting to the right at 0,= 45° to the hori- zontal, and a force P…
Show that vsound in air=sqrt(1.4kT/M) is equal to v=331 m/s sqrt(T/273)
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Q3. A 750 g sample of Gravel in the SSD condition in air and weighed 480 g when immersed in water. Also, a 350 g sample of Sand in the SSD condition in air and weighed 210 g when immersed in water. Answer the following questions: B) If some sample from same batch after being exposed to air dry condition for some time weighed for gravel 670 g in air and weighed 99 g after they immersed in water for 2 hours, and for sand 320 g in air and weighed 40 g after they immersed in water for 2 hours. Calculate the moisture content, .MC(SSD), of the air-dried sand and gravel at that time B-1) the MC (SSD) of the Gravel 1.546 4.236 2.453 3.331 B-2) the MC (SSD) of the Sand 3.800 O 2.988 2.761 4.811 O O O
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An air bubble rises from the bottom of a well where the temperature is 25 0 C, to thesurface where the temperature is 27 0 C. Find the percent increase in the volume of thebubble if the depth of the well is 5m. Atmospheric pressure is 101,528 Pascals.
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