Solve the partial differential equation ди - sinxtan? y given that дхду -= cos x when y = 0 and u=ywhen x = 0? ax %3D %3D A) u = (tany-y) (xsinx + (1- x²)). B)u = (tany-y) (xsinx +(1– x²)). + cosx + tany + 2y + cosx + coty+2y %3D C)u = (tany +y) (xsinx + (1-x²)) + sinx + tany + 2y %3D D)u = (tany +y) (x sinx +(1-x)) + sinx + tany + 2y E)u = (tany-y) (xsin+(1+x*)i) + sinx + F)u = (tany- y)(xcos"x+(1-x*)) + sinx + tany + 2y G)u = (tany- y)(sinx+ (1– x*)) + sinx + tany + 2y H)u = (tany-y) (xsinx + (1 – x*)* + %3D %3D tany +2y %3D %3D x+(1-x²)i)+ sinx - tany + 2y

Solve the partial differential equation ди - sinxtan? y given that дхду -= cos x when y = 0 and u=ywhen x = 0? ax %3D %3D A) u = (tany-y) (xsinx + (1- x²)). B)u = (tany-y) (xsinx +(1– x²)). + cosx + tany + 2y + cosx + coty+2y %3D C)u = (tany +y) (xsinx + (1-x²)) + sinx + tany + 2y %3D D)u = (tany +y) (x sinx +(1-x)) + sinx + tany + 2y E)u = (tany-y) (xsin+(1+x)i) + sinx + F)u = (tany- y)(xcos"x+(1-x)) + sinx + tany + 2y G)u = (tany- y)(sinx+ (1– x)) + sinx + tany + 2y H)u = (tany-y) (xsinx + (1 – x)* + %3D %3D tany +2y %3D %3D x+(1-x²)i)+ sinx - tany + 2y

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter11: Differential Equations

Section11.1: Solutions Of Elementary And Separable Differential Equations

Problem 10E

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