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Solve for Vmax and Mmax.    Please help me with this one. Please use the second photo as reference. Subject: Strength of Materials Topic: Moving Loads

Solve for Vmax and Mmax.    Please help me with this one. Please use the second photo as reference. Subject: Strength of Materials Topic: Moving Loads

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter12: Electric Current And Related Variables In Engineering
Section12.2: Electrical Circuits And Components
Problem 6BYG
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Solve for Vmax and Mmax. 

 

Please help me with this one. Please use the second photo as reference.

Subject: Strength of Materials

Topic: Moving Loads

Sample Prslem #1 Atruck with axle loods 4 40 kn and coka on a wheel Anle bals- 30ka ard 5ohn basey 5m nolls across a 10-mpan Compute the maximum shearing shearig Reg'a : Max V and max M Sanple prosleata Given : wheel base - 4M Span leryth= 8m force ard maximum bending momerty Coution: 36kn R-so kn JR-100ao ka 3m 1 A 2m 4M ŽMzoka = Rd. 8rd = 5X4) ; For Max Shear 20 kn 4m %3D ZMA = Rd lood = 60(5) , d= 3m For Max. Shear 40 hn %3D K 4m Goha R. MRI 5m 8Ry 30(4)+50c8) 5 Ame Tom and EMR, =0 TORE 40 C5)+ ao Cc0) RiF 80 kn = Vmãx For Max. Moment R-bo For Maxe Moment, (30-kn load) 2.75 M %3D 4m. 4m R2 ZMR2=0j BR,; R,27.5A Made 27.52.) = 75. G05 n. m 50kn bada 5ela 3. af m 4m R, ZMR, ° loR2=/00(4) ) Rz Tpco 30m Max moment to the night 4 eo-kn aad 4m 4m Ri =0 ; 8R2 = 60 (3. a); R- 325h 'Ry ZMR, =0 Mada - 32.5 (3. ar) Mo ln - /05.625 kn. m %3D Maska - 40C4) = leo kn.m
Transcribed Image Text:Sample Prslem #1 Atruck with axle loods 4 40 kn and coka on a wheel Anle bals- 30ka ard 5ohn basey 5m nolls across a 10-mpan Compute the maximum shearing shearig Reg'a : Max V and max M Sanple prosleata Given : wheel base - 4M Span leryth= 8m force ard maximum bending momerty Coution: 36kn R-so kn JR-100ao ka 3m 1 A 2m 4M ŽMzoka = Rd. 8rd = 5X4) ; For Max Shear 20 kn 4m %3D ZMA = Rd lood = 60(5) , d= 3m For Max. Shear 40 hn %3D K 4m Goha R. MRI 5m 8Ry 30(4)+50c8) 5 Ame Tom and EMR, =0 TORE 40 C5)+ ao Cc0) RiF 80 kn = Vmãx For Max. Moment R-bo For Maxe Moment, (30-kn load) 2.75 M %3D 4m. 4m R2 ZMR2=0j BR,; R,27.5A Made 27.52.) = 75. G05 n. m 50kn bada 5ela 3. af m 4m R, ZMR, ° loR2=/00(4) ) Rz Tpco 30m Max moment to the night 4 eo-kn aad 4m 4m Ri =0 ; 8R2 = 60 (3. a); R- 325h 'Ry ZMR, =0 Mada - 32.5 (3. ar) Mo ln - /05.625 kn. m %3D Maska - 40C4) = leo kn.m
Gokn asla Ri 10m Ry
Transcribed Image Text:Gokn asla Ri 10m Ry
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