Solve for the Following Shear force equation for segment AB. a.-16.65 psf X squared b. 16.65 psf X squared c. -16.75 psf X squared d. 16.75 psf X squared Bending moment equation for segment AB. a.-5.40 psf X cube b. 5.45 psf X cube c. -5.55 psf X cube d. 6.55 psf X cube Shear force equation for segment BC. a. 2000 lb - 200 lb/ft ( X) b. 2100 lb - 300 lb/ft ( X) c. 2150 lb - 300 lb/ft ( X) d. 3000 lb - 200 lb/ft ( X)

Solve for the Following Shear force equation for segment AB. a.-16.65 psf X squared b. 16.65 psf X squared c. -16.75 psf X squared d. 16.75 psf X squared Bending moment equation for segment AB. a.-5.40 psf X cube b. 5.45 psf X cube c. -5.55 psf X cube d. 6.55 psf X cube Shear force equation for segment BC. a. 2000 lb - 200 lb/ft ( X) b. 2100 lb - 300 lb/ft ( X) c. 2150 lb - 300 lb/ft ( X) d. 3000 lb - 200 lb/ft ( X)

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter6: Beams And Cables

Section: Chapter Questions

Problem 6.76P: The 50-ft measuring tape weighs 2.4 lb. Compute the span L of the tape to four significant figures.

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Concept explainers

Bending Moment

In general, we can define the bending moment as the reaction induced when a certain amount of load or force is applied to an element which makes it bend.

Question

Solve for the Following

Shear force equation for segment AB.

a.-16.65 psf X squared

b. 16.65 psf X squared

c. -16.75 psf X squared

d. 16.75 psf X squared

Bending moment equation for segment AB.

a.-5.40 psf X cube

b. 5.45 psf X cube

c. -5.55 psf X cube

d. 6.55 psf X cube

Shear force equation for segment BC.

a. 2000 lb - 200 lb/ft ( X)

b. 2100 lb - 300 lb/ft ( X)

c. 2150 lb - 300 lb/ft ( X)

d. 3000 lb - 200 lb/ft ( X)

A
6 ft-
200 lb/ft
B
CA
1200 lb. ft
★4 ft —— 4 ft -
D

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