3. A sample of pure CaCO3 (MW 100.09) weighing 0.4148 g is dissolved in 1: 1 hydrochloric acidand the solution is diluted to 500 mL in a volumetric flask. A 50.0 –mL aliquot is withdrawnwith a pipet and placed in an Erlenmeyer flask. The solution is titrated with 40.34 mL of anEDTA solution using Erichrome Black T indicator. Calculate the molarity of the EDTA solution.Hint: This problem involves analysis of an aliquot from a standard solution. In solving for themolarity of the EDTA solution, you should consider the amount of the standard in thealiquot which is used in the titration process. In this analysis, one mole of CaCO3 reactswith one mole of EDTA.

Moles of CaCO3=mass/molar mass=0.4148g/100.09g/mole=0.00414moles…

Answered: SOlution is titrated with 40.34 mL of…

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SOlution is titrated with 40.34 mL of an pr. Calculate the molarity of the EDTA solution.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.17QAP

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Question

3. A sample of pure CaCO3 (MW 100.09) weighing 0.4148 g is dissolved in 1: 1 hydrochloric acid
and the solution is diluted to 500 mL in a volumetric flask. A 50.0 –mL aliquot is withdrawn
with a pipet and placed in an Erlenmeyer flask. The solution is titrated with 40.34 mL of an
EDTA solution using Erichrome Black T indicator. Calculate the molarity of the EDTA solution.
Hint: This problem involves analysis of an aliquot from a standard solution. In solving for the
molarity of the EDTA solution, you should consider the amount of the standard in the
aliquot which is used in the titration process. In this analysis, one mole of CaCO3 reacts
with one mole of EDTA.

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