simple c++ and donot use array and adavace logic Write a function named "reduce" that takes two integers (positive or negative) arguments (as reference), call them "num" and "denom", treats them as the numerator and denominator of a fraction, and reduces the fraction. The function should return the value 0 (to indicate failure to reduce: if either of the two arguments is zero) and should return the value 1 otherwise. Function Prototype: bool reduce(int & num,int & denom); Example01:****************************************************** num= 10 denom=50 after calling reduce function 1. function must return 1 2. updated value of num will be 1 3. updated value of denom will be 5 Example02: ****************************************************** num= 38 denom= 6 after calling reduce function 1. function must return 1 2. updated value of num will be 19 3. updated value of denom will be 3 Example03: ****************************************************** num= 3 denom= -27 after calling reduce function 1. function must return 1 2. num will be 1 3. denom will be -9 Example04: ****************************************************** num= -3 denom= -27 after calling reduce function 4. function must return 1 5. num will be 1 6. denom will be 9
use simple c++ and donot use array and adavace logic Write a function named "reduce" that takes two integers (positive or negative) arguments
(as reference), call them "num" and "denom", treats them as the numerator and
denominator of a fraction, and reduces the fraction.
The function should return the value 0 (to indicate failure to reduce: if either of the two
arguments is zero) and should return the value 1 otherwise.
Function Prototype: bool reduce(int & num,int & denom);
Example01:******************************************************
num= 10
denom=50
after calling reduce function
1. function must return 1
2. updated value of num will be 1
3. updated value of denom will be 5
Example02: ******************************************************
num= 38
denom= 6
after calling reduce function
1. function must return 1
2. updated value of num will be 19
3. updated value of denom will be 3
Example03: ******************************************************
num= 3
denom= -27
after calling reduce function
1. function must return 1
2. num will be 1
3. denom will be -9
Example04: ******************************************************
num= -3
denom= -27
after calling reduce function
4. function must return 1
5. num will be 1
6. denom will be 9
Example05: ******************************************************
num= 3
denom= 0
after calling reduce function
1. function must return 0
2. num will be 3
3. denom will be 0
Note:
• Do not use any built-in (math) functions (cmath library).
take input and display output in main function
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