SELECT DISTINCT Students.ID, Name FROM Students, Grades WHERE Students.ID = Grades.ID; Exp1 Exp2 Neither

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Consider the following two tables where Grades.ID is a foreign key to Students.ID.
Students (ID, Name)
Grades(ID, Course_No, Grade)
Consider the following relational algebra expressions:
Exp1 := TtID, Name (Students ¤ Grades)
Exp2 := TStudents.ID, Name (Students x Grades)
In the following questions, select whether each query is equivalent to Exp1, Exp2, or
Neither.
Transcribed Image Text:Consider the following two tables where Grades.ID is a foreign key to Students.ID. Students (ID, Name) Grades(ID, Course_No, Grade) Consider the following relational algebra expressions: Exp1 := TtID, Name (Students ¤ Grades) Exp2 := TStudents.ID, Name (Students x Grades) In the following questions, select whether each query is equivalent to Exp1, Exp2, or Neither.
SELECT DISTINCT Students.ID, Name FROM Students, Grades
WHERE Students.ID = Grades.ID;
Exp1
Exp2
Neither
Transcribed Image Text:SELECT DISTINCT Students.ID, Name FROM Students, Grades WHERE Students.ID = Grades.ID; Exp1 Exp2 Neither
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