S)-2-bromobutane reacts with H2O under the SN1 conditions to form two substitution products: one with the same relative configuration as the reactant (i. e. the product is (S)-2-butanol) and the other with the inverted configuration (i. e. the product is (R)-2-butanol). a) Explain how this happens (the formation of two stereoisomers – one with an inverted configuration and the other with a retained configuration). b) Which stereoisomer (configuration) will typically have a higher yield? Explain.

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4. (S)-2-bromobutane reacts with H2O under the SN1 conditions to form two substitution products: one with the same relative configuration as the reactant (i. e. the product is (S)-2-butanol) and the other with the inverted configuration (i. e. the product is (R)-2-butanol).

a) Explain how this happens (the formation of two stereoisomers – one with an inverted configuration and the other with a retained configuration). 

b) Which stereoisomer (configuration) will typically have a higher yield? Explain.

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