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Remember that B (n, p) → P(x) = (")p²q¹-² with the Binomial Coefficient n! (2)= So for example: (39) = 10! 3!(10-3)! = 10! 31-7! = 10-9-8-7! 3!-7! = 10-9-8 3! = 10-9-8 3-2-1 = 10.3.4 = 120 Thus given B (10, 0.4) and want to Find P(3) -> P (3) = (3)0.4³ (1-0.4) ¹0-3 = 120 0.4³ -0.67≈ 0.215 Given that you have B(7, 0.712) find P(3) to the nearest thousandth

Remember that B (n, p) → P(x) = (")p²q¹-² with the Binomial Coefficient n! (2)= So for example: (39) = 10! 3!(10-3)! = 10! 31-7! = 10-9-8-7! 3!-7! = 10-9-8 3! = 10-9-8 3-2-1 = 10.3.4 = 120 Thus given B (10, 0.4) and want to Find P(3) -> P (3) = (3)0.4³ (1-0.4) ¹0-3 = 120 0.4³ -0.67≈ 0.215 Given that you have B(7, 0.712) find P(3) to the nearest thousandth

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 55RE
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Question 13 Remember that B (n, p) → P(x) = (2) p q- with the Binomial Coefficient n! So for example: (39) - 10! 3!(10-3)! = 10! 31-7! - 10-9-8-7! 3!-7! 10-9-8 3! - 10-9-8 3-2-1 = 10 3 4 120 . . Thus given B (10, 0.4) and want to Find P(3) -> P (3)= (3)0.4³ (10.4) ¹0-3 = 120 0.4³ 0.67≈ 0.215 Given that you have B( 7, 0.712) find P(3) to the nearest thousandth
Transcribed Image Text:Question 13 Remember that B (n, p) → P(x) = (2) p q- with the Binomial Coefficient n! So for example: (39) - 10! 3!(10-3)! = 10! 31-7! - 10-9-8-7! 3!-7! 10-9-8 3! - 10-9-8 3-2-1 = 10 3 4 120 . . Thus given B (10, 0.4) and want to Find P(3) -> P (3)= (3)0.4³ (10.4) ¹0-3 = 120 0.4³ 0.67≈ 0.215 Given that you have B( 7, 0.712) find P(3) to the nearest thousandth
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