Answer the following blanks,V=60R1=300R2=600 60V1, V2Figure 8-2.POWERPOWER SUPPLIEDCALCULATEDVALUESDISSIPATED(, x En)V, = VPR1%3DPs =V2 = V1, = APR2 =W%DP, = _W12 = A%3D

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Answered: R, I, V2 60V V, Figure 8-2. CALCULATED…

R, I, V2 60V V, Figure 8-2. CALCULATED POWER POWER SUPPLIED VALUES DISSIPATED (1, x En) V, = V %D R1 V2 = V PR2 =. Ps = W 1, =_A P, = _W 2= A A 009 R.

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 4PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

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Concept explainers

Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.

Question

Answer the following blanks, V=60 R1=300 R2=600

60V
1, V2
Figure 8-2.
POWER
POWER SUPPLIED
CALCULATED
VALUES
DISSIPATED
(, x En)
V, = V
PR1
%3D
Ps =
V2 = V
1, = A
PR2 =
W
%D
P, = _W
12 = A
%3D

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