Question 5 Listen You are a genetic counselor. Joanie has a son with Down Syndrome and a daughter without Down Syndrome. Neither of her parents has Down Syndrome, but she has an aunt and uncle with Down Syndrome. Based on this information, it is likely that this is a case of translocation Down syndrome and you can verify this by doing a karyotype on Joanie's son. a) True b) False

Question 5 Listen You are a genetic counselor. Joanie has a son with Down Syndrome and a daughter without Down Syndrome. Neither of her parents has Down Syndrome, but she has an aunt and uncle with Down Syndrome. Based on this information, it is likely that this is a case of translocation Down syndrome and you can verify this by doing a karyotype on Joanie's son. a) True b) False

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter4: Pedigree Analysis In Human Genetics

Section: Chapter Questions

Problem 3QP: Pedigree Analysis Is a Basic Method in Human Genetics Using the pedigree provided, answer the...

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Question 9 Consider that a certain gene is a maternal effect gene and that the allele for dark brown pigment is incompletely dominant to the allele for no pigment (white). The incomplete dominant phenotype is light tan. If a heterozygous female is crossed with heterozygous male, what will be the phenotypic ratio of the progeny? A) 1 dark brown: 2 light brown: 1 white. B) 3 dark brown: 1 white C). all dark brown D) all light tan E) cannot be determined CS Scanned with CamScanner
The results of a paternity test using short tandem repeatsare listed in the table below. Who’s the daddy? How sureare you?
The Meeting Sarah stared blankly at the blue paisley wallpaper. Her husband Mike sat by her side, bending and unbending a small paper clip. “Sarah and Michael, it’s good to meet you,” welcomed the genetic counselor, as she entered the room. “I apologize for being late, but I was just meeting with another couple. Let’s see, you’d like to have a child, but you’re concerned because of your family history of cystic fibrosis.” “Yes,” Sarah replied softly. “Mike and I met at a CF support group meeting a few years ago. He had a younger brother who died of cystic fibrosis, and I had a younger sister. We saw the painful lives they had—difficulty breathing, the constant respiratory infections. Although the treatments for CF are better now, we just don’t know if we can…” she trailed off. “I can certainly understand your concern,” the genetic counselor responded sympathetically. “That’s where I hope to help, by providing as much information and advice as I can. I’m glad that you came to see me…
A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) This woman is phenotypically normal. Does thissurprise you? Why or why not? Under what circumstancesmight you expect a phenotypic effect of such arearrangement?
Question #1 Since experimental crosses are not performed in humans, how do we know how traits are inherited? State the name of the analysis/ chart and explain in at least one sentence.
Which members of the pedigree could have been carriers, and which might have been the source of the mutation?
Pedigree Analysis Is a Basic Method in Human Genetics Using the pedigree provided, answer the following questions. a. Is the proband male or female? b. Is the grandfather of the proband affected? c. How many siblings does the proband have, and where is he or she in the birth order?
Campomelic dysplasia (CMD1) is a congenital humansyndrome featuring malformation of bone and cartilage.It is caused by an autosomal dominant mutation of agene located on chromosome 17. Consider the followingobservations in sequence, and in each case, draw whateverappropriate conclusions are warranted.(a) Of those with the syndrome who are karyotypically46,XY, approximately 75 percent are sex reversed,exhibiting a wide range of female characteristics.(b) The nonmutant form of the gene, called SOX9, isexpressed in the developing gonad of the XY male,but not the XX female.(c) The SOX9 gene shares 71 percent amino acid codingsequence homology with the Y-linked SRY gene.(d) CMD1 patients who exhibit a 46,XX karyotypedevelop as females, with no gonadal abnormalities.
Question 2. A widow's peak hairline is a dominant trait and a straight hairline is a recessive trait. What will be the genotypes and phenotypes of children of a homozygous dominant parent and a heterozygous parent? a) Construct a Punnett Square - List gametes in the area with the dashed line and the genotypes of the offspring in the area with the sold line. b) Genotypes of Children-c) Phenotypes of children-
QUESTION 7 A trihybrid individual with the genotype AaDdEe is testcrossed with an aaddee individual. The resulting offspring are as follows: ADe 880 aDE 67 AdE 45 ade 4 ADE 3 aDe 57 Ade 57 adE 887 Total = 2000 a) Determine the allele arrangement and gene order in the trihybrid parent. Give your answer using the PQr/pqR notation. b) Draw a chromosome map for these genes. Give your map distances to two decimal places. (Use underline or underscore (_) to draw the line for the map)
Question 1: In tomatoes, round fruit (O) is dominant to oblong fruit (o). Write as much as possible of the genotypes of: (A) A plant from a homozygous round-fruited stock (B) A plant from an oblong strain (C) A round-fruited plant which resulted from a testcross (D) A oblong-fruited plant which resulted from the cross of two round-fruited ones.
PLEASE ANSWER THE FOLLOWING LETTERS: a,b,c, and d Examine the pedigree of the McGraw family shown below. Certain individuals in this family are affected by a brain condition that makes them more susceptible to vertigo. As a genetic counselor, you interview the family and draw DNA samples. You discover that the condition is caused by a mutation that changes the sequence 5’GCATTC3’ to 5’GAATTC3’ introducing an EcoRI cut site. You decide to amplify a 1200bp fragment from the DNA that spans this mutation and then digest it with EcoRI. You run the results on a gel next to a marker that shows bands at 2000bp, 1200bp, 900bp, 800bp, and 400bp. Some individuals from the pedigree are identified on the gel.