QUESTION 5 A battery connected in the circuit given below has an emf of 20.0 V and an internal resistance of 5.51 milli-ohm. The current flowing through the circuit is 31.6 A. a) Find the resistance R in the circuit upto three significant figures. b) Calculate the voltage drop across the internal resistance r c) ) Calculate the voltage drop across the external resistance R Submit the resistance you obtained in a) (with three significant figures) as your answer. You are required to show your work for a), b) and c) in the file you submit.

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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
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Chapter21: Circuits And Dc Instruments
Section: Chapter Questions
Problem 53PE: A 1,00-?O voltmeter is placed in parallel with a 75.0kresistor in a circuit, (a) Draw a circuit...
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QUESTION 5
A battery connected in the circuit given below has an emf of 20.0 V and an internal resistance of 5.51 milli-ohm. The current flowing through the
circuit is 31.6 A.
a) Find the resistance R in the circuit upto three significant figures.
b) Calculate the voltage drop across the internal resistance r
c)) Calculate the voltage drop across the external resistance R
Submit the resistance you obtained in a) (with three significant figures) as your answer.
You are required to show your work for a), b) and c) in the file you submit.
Transcribed Image Text:QUESTION 5 A battery connected in the circuit given below has an emf of 20.0 V and an internal resistance of 5.51 milli-ohm. The current flowing through the circuit is 31.6 A. a) Find the resistance R in the circuit upto three significant figures. b) Calculate the voltage drop across the internal resistance r c)) Calculate the voltage drop across the external resistance R Submit the resistance you obtained in a) (with three significant figures) as your answer. You are required to show your work for a), b) and c) in the file you submit.
I
r
1
I a
|
E
+
b
M
f
C
R
r
2
4
Transcribed Image Text:I r 1 I a | E + b M f C R r 2 4
Expert Solution
Step 1

Given,

E = 20.0 V

r = 5.51 mili-ohm

I = 31.6 A

 

(a) Now, 

I = E / (R+r)

R = (E / I) - r

R = (20 / 31.6) - 0.00551

R = 0.627 ohm

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