Question 2. A three-phase, delta-connected, 2-pole 1000 V, 50Hz asynchronous motor rotates at 2920 rpm. The equivalent circuit parameters reduced to the stator are given below. The friction of this asynchronous motor Since the losses are neglected, using the equivalent circuit given below a) Calculate the iron losses of the motor. (Other formats where the result will be entered in Watts as three digits after the comma will not be accepted.) R_1-0,70 X1-0,30 Gc=0,3 mS P20401 X2-0.40 B_m=0,5 mS R₁ 19 11 jx, m m M

Delmar's Standard Textbook Of Electricity
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Chapter32: Three-phase Motors
Section: Chapter Questions
Problem 6RQ: Name three factors that determine the torque produced by an induction motor.
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Question 2. A three-phase, delta-connected, 2-pole 1000 V, 50Hz asynchronous motor rotates at 2920 rpm. The
equivalent circuit parameters reduced to the stator are given below. The friction of this asynchronous motor
Since the losses are neglected, using the equivalent circuit given below
a) Calculate the iron losses of the motor. (Other formats where the result will be entered in Watts as
three digits after the comma will not be accepted.)
R_1-0,70
X1-0,30
Gc-0,3 mS
R2-0.40
X2-0.40
B_m=0,5 mS
4₁
V. GB
19
jX₂
b) Calculate the output power of the motor. (The result will be written in kilowatts with three digits
after the comma, and other units will not be accepted.)
c) Calculate the input power of the motor. (The result will be written in kilowatts with three digits after
the comma, and other units will not be accepted.)
d) Calculate the efficiency of the engine. (If the result is 98,586% with three digits after the comma, only 98,586
Other units will not be accepted.)
e) Calculate the torque of the motor. (The result will be entered in Newton meters (Nm) as three digits after the
decimal point.)
Transcribed Image Text:Question 2. A three-phase, delta-connected, 2-pole 1000 V, 50Hz asynchronous motor rotates at 2920 rpm. The equivalent circuit parameters reduced to the stator are given below. The friction of this asynchronous motor Since the losses are neglected, using the equivalent circuit given below a) Calculate the iron losses of the motor. (Other formats where the result will be entered in Watts as three digits after the comma will not be accepted.) R_1-0,70 X1-0,30 Gc-0,3 mS R2-0.40 X2-0.40 B_m=0,5 mS 4₁ V. GB 19 jX₂ b) Calculate the output power of the motor. (The result will be written in kilowatts with three digits after the comma, and other units will not be accepted.) c) Calculate the input power of the motor. (The result will be written in kilowatts with three digits after the comma, and other units will not be accepted.) d) Calculate the efficiency of the engine. (If the result is 98,586% with three digits after the comma, only 98,586 Other units will not be accepted.) e) Calculate the torque of the motor. (The result will be entered in Newton meters (Nm) as three digits after the decimal point.)
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