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- How does a parameter query differ from a select query?reate a query that SELECT all of the EMPLOYEES from the EMPLOYEE TABLE that are Mangers. Include Employee ID first name, Lastname and Salary (Hint: Self Join) /* Write a query the gives the Employee ID first name, Lastname and Salary and Project Number of EMPLOYEES who aren't currently assigned to a project (hint outer join) Create a query that lists the lastnme, edlevel , job, the number of years they've worked as of Jan 01/2002 ( hint : year function Jan 01/2002 minus hiredate), and their salary. Get the employees that have the same Job as the employee named starts with J (hint subquery from employee) and hiredate < Jan 01/2002 Sort the listing by highest salary first. */select * from cast where cast_id=162652763; Use explain to display the query plan without creating any index. Now create an index to speed up the query. Use explain and timer to show the improvement.
- Using the Winners table from Figure 12-2, write a parameter query that selects theActor and Actress fields for the year provided by the user.Query 3: Write a parameter query to display the names of all prospects each member tried to recruit based on the member’s first name and the member’s last name you input. List the member’s First Name, member’s Last Name, prospect’s First Name, and prospect’s Last Name (in this order in the query grid). Display the member’s First Name Heading as Member First Name, member’s Last Name Heading as Member Last Name, prospect’s first name heading as Prospect First Name, and prospect’s last name heading as Prospect Last Name. Sort the list by Member Last Name, Member First Name, Prospect Last Name, and Prospect First Name, all ascending order. (WE ARE USING ACCESS SO I AM JUST TRYING TO UNDERSTAND WHAT TO PUT AND PLUG IN ETC. USE MY PICTURES AS REFERRENCE!)Description The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +--- | Id | Name | Salary | ManagerId | +---- | 1 | 2 | 3 | 4 +---- | Joe | 70000 | 3 | Henry | 80000 | 4 | Sam | Max Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager. + | Employee | + | Joe + | 60000 | NULL | 90000 | NULL I
- Create a query that SELECT all of the EMPLOYEES from the EMPLOYEE TABLE that are Mangers. Include Employee ID first name, Lastname and Salary (Hint: Self Join) /* Write a query the gives the Employee ID first name, Lastname and Salary and Project Number of EMPLOYEES who aren't currently assigned to a project (hint outer join) Create a query that lists the lastnme, edlevel , job, the number of years they've worked as of Jan 01/2002 ( hint : year function Jan 01/2002 minus hiredate), and their salary. Get the employees that have the same Job as the employee named starts with J (hint subquery from employee) and hiredate < Jan 01/2002 Sort the listing by highest salary first. */ /* Create a table with a COMPOSITE PRIMARY KEY (mininum 3 columns the table) and the second table will have will have a foreign keys to the PRIMARY KEY Run the Reverse Engineer function in MySQL workbench on these tables and provide the .MWB file in your submission Create a table in 1NF…DROP TABLE IF EXISTS Worker; CREATE TABLE Worker ( ); 0 INSERT ); WORKER_ID INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT, FIRST NAME TEXT, LAST NAME TEXT, SALARY INTEGER (15), JOINING DATE DATETIME, DEPARTMENT CHAR (25) INTO Worker (WORKER_ID, FIRST_NAME, LAST_NAME, SALARY, JOINING_DATE, DEPARTMENT) VALUES 'Arora', 100000, '14-02-20 09.00.00', 'HR'), (001, 'Monika', (002, 'Niharika', 'Verma' 80000, '14-06-11 09.00.00', 'Admin'), 'HR'), 'Admin'), Admin'), 'Account'), 'Kumar', 75000, '14-01-20 09.00.00', 'Account') DROP TABLE IF EXISTS Bonus; CREATE TABLE Bonus ( ); (003, 'Vishal' 'Singhal', 300000, '14-02-20 09.00.00', (004, 'Amitabh 'Singh', 500000, '14-02-20 09.00.00', (005, 'Vivek' 'Bhati', 500000, '14-06-11 09.00.00'. (006, 'Vipul', 'Diwan' 200000, '14-06-11 09.00.00', (007, 'Satish' (008, 'Geetika', 'Chauhan', 90000, '14-04-11 09.00.00', 'Admin'); WORKER_REF_ID INTEGER, BONUS AMOUNT INTEGER(10), BONUS_DATE DATETIME, FOREIGN KEY (WORKER_REF_ID) REFERENCES Worker (WORKER_ID) ON DELETE…In Sql Oracle Apex application, Using GROUPING SETS, write a query to show the following groupings:• department_id, manager_id, job_id• manager_id, job_id• department_id, manager_id
- Code three tests: 1) for a student who has courses 2) for student who does not have courses 3) a non-existing student ID. For each test, display the value of the student ID that was passed to the function and the result returned by the function. Also, run a supportive SELECT query or queries that prove the test results are correct.Could you do typing the query here please?Employee(empno, ename, street, city, mgrssn) work_project(eno, pno, number_of_hours) Write a query and optimize it to find employee name and project number in which they work and who live in "New_york". Identify the type of indexing to be applied on 'empno' in Employee Table.
