QUESTION 16 You have a pure breeding plant with red flowers, yellow seeds and red-veined leaves. You cross this with another pure breeding plant that has white flowers, pink seeds and yellow leaf veins. All of the offspring (F1) have white flowers, yellow seeds and orange leaf veins. Assuming all three loci are independently assorting, use this information to answer the following question: Which set of terms can correctly fill in the blanks in the following sentence? The trait is recessive to the trait. O a. Pink seed ; yellow seed O b. Yellow seed; pink seed. Oc. Orange-vein leaf; red-vein leaf O d. White flower; red flower. O e. Both a and d are correct
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- Variations on a Theme by Mendel Pea plants usually have white or red flowers. A strange pea-plant variant is found that has pink flowers. A selfcross of this plant yields the following phenotypes: 30 red flowers 62 pink flowers 33 white flowers What are the genotypes of the parents? What is the genotype of the progeny with red flowers?More Crosses with Pea Plants: The Principle of Independent Assortment In pea plants, long stems are dominant to short stems, purple flowers are dominant to white, and round peas are dominant to wrinkled. Each trait is determined by a single, different gene. A plant that is heterozygous at all three loci is self-crossed, and 2,048 progeny are examined. How many of these plants would you expect to be long stemmed with purple flowers, producing wrinkled peas?More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible genotypes of the following parents by analyzing the phenotypes of their children. In this case, we will assume that brown eyes (B) is dominant to blue (b) and that right-handedness (R) is dominant to left-handedness (r). a. Parents: brown eyes, right-handed brown eyes, right-handed Offspring: 3/4 brown eyes, right-handed 1/4 blue eyes, right-handed b. Parents: brown eyes, right-handed blue eyes, right-handed Offspring: 6/16 blue eyes, right-handed 2/16 blue eyes, left-handed 6/16 brown eyes, right-handed 2/16 brown eyes, left-handed c. Parents: brown eyes, right-handed blue eyes, left-handed Offspring: 1/4 brown eyes, right-handed 1/4 brown eyes, left-handed 1/4 blue eyes, right-handed 1/4 blue eyes, left-handed
- O e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook AirHeight of the plant if a homozygous tall pea plant is crossed with a homozygous short pea plant, what are the possible genotype and phenotypes of the offspring? Legend: T- tall pea plant t- short pea plant Genotypes of the parents TT x tt Question 1. what is the genotypic ratio 2. what are the possible phenotypes of the offspring? 3. What is the phenotypic ratio? 4. what is the probability of having a short trait?IN D Genetics Tutorial 3-Satish Sasikumar 30-12-2020.pdf In radishes, flower color may be red, purple, or white. The edible portion of the radish may be long or oval. When only flower color is studied, no dominance is evident, and red white crosses yield all purple. If these F1 purples are interbred, the F2 generation consists of 1/4 red: 1/2 purple: 1/4 white. Regarding radish shape, long is dominant to oval in a normal Mendelian fashion. (a) Determine the F1 and F2 phenotypes from a cross between a true-breeding red, long radish and a radish that is white and oval. Be sure to define all gene symbols at the start. (b) A red oval plant was crossed with a plant of unknown genotype and phenotype, yielding the following offspring: 103 red long: 101 red oval 98 purple long: 100 purple oval Determine the genotype and phenotype of the unknown plant.
- PURPLE VESTIGIAL DIHYBRID TESTCROSS In the parental generation, you mate a pure-breeding wild-type female (put/put.vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (put/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (put/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Wild-type Purple, vestigial Vestigial Purple Genotype Tester Gamete Dihybrid Gamete Number 437 417 77 59 Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete…/16 disc-shaped fruit : */16 spherical fruit : /16 long fruit. Give the genotypes of the F, progeny. 32. Some sweet-pea plants have purple flowers and others have white flowers. A homozygous variety of sweet pea that has purple flowers is crossed with a homozygous variety that has white flowers. All the F, have purple flowers. When these F, self-fertilize, the F, appear in a ratio of /16 purple to 7/16 white. a. Give genotypes for the purple and white flowers in these crosses. b. Draw a hypothetical biochemical pathway to explain the production of purple and white flowers in sweet peas. 33. *Refer to the discussion of how coat color and pattern are determined in dogs.Topic: Penetrance. Petal number is controlled by a single gene in merigonias. The gene has a completely dominant wild type allele F that makes a plant have five petals and a mutant recessive six petal allele(f). However the six petal trait is only 50% penetrant. You do the cross Ff x Ff. What fraction of the progeny do you have the 6 petals? what is the meaning for 50% penetrant.
- ( Question 17 of 17 > Attempt 8 A summer squash plant that produces disc-shaped fruit is crossed with a summer squash plant that produces long fruit. All of the F1 have disc-shaped fruit. When the F1 are intercrossed, F2 progeny are produced in the ratio 9/16 disc-shaped fruit, 6/16 spherical fruit, 1/16 long fruit. Give the genotypes of the F2 progeny. Place two genes in each bin to form a complete genotype. F2 Phenotype Genotype Answer Bank 9/16 disc-shaped bb aa B 6/16 spherical A_ 1/16 long Question Source: Pierce 6e - Genetics: A Conceptual Approach| Publisher: W.H. FreemanBLACK VESTIGIAL DIHYBRID TESTCROSS In the parental generation, you mate a pure-breeding wild-type female (bl+/blt.vg+/vg+) with a pure-breeding black, vestigial (bl/bl vg/vg) to produce an F1 generation that is all wild-type (bl+/bl vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (bl+/bl vg+/vg) with tester males, which are black, vestigial (bl/bl;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number 440 Wild-type 394 108 135 Black, vestigial Vestigial Black Copy the table into your notes and derive the dihybrid gametes following the example in the previous section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed bl vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete…must answer all other don't answer i need all part solvve Two pea plants are crossed, which are purebred. A father is round, terminal, violet and wrinkled, while the other expresses the phenotypes alternate rough, axial, white, and swollen. The four pairs of characters alternatives are regulated by four genes, each located in different chromosomes. In Fx only the characters round, axial, purple and puffy. In F2 all possible combinations of these characters according to Mendelian inheritance. (a) to what conclusions we can reach about the inheritance of these characters, based on the F1 results? (b) In the results of F2, what phenotype will appear more often? Write a mathematical expression that predict the probability of occurrence of said phenotype. (c) In the results of F2, which phenotype will appear less frequently? write an expression mathematics that predicts this probability. (d) In the F2 generation, with what probability will each of the two phenotypes of P1 appear? (e) If a…