Question 1. Two components in an HPLC separation have retention times that differ by 22 s. The first peak elutes in 10.5 min and the peak widths are approximately equal. (a) Calculate the minimum number of theoretical plates needed to achieve an acceptable resolution (b) Explain why it is possible for each compound to have a different number of theoretical plates Show all your working and the final answer.

Question 1. Two components in an HPLC separation have retention times that differ by 22 s. The first peak elutes in 10.5 min and the peak widths are approximately equal. (a) Calculate the minimum number of theoretical plates needed to achieve an acceptable resolution (b) Explain why it is possible for each compound to have a different number of theoretical plates Show all your working and the final answer.

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter89: Thin-layer Chromatography

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Two components in an HPLC separation have retention times that differ by 22 s. The first peak elutes in 10.5 min and the peak widths are approximately equal. Calculate the minimum number of theoretical plates needed to achieve an acceptable resolution
What are the disadvantages of uses the Thick layer stationary phase in Thin layer Chromatography (TLC)? Please shortly write at your own words. (4-5 lines maximum ).
A peak with a retention time of 10 minutes has a width at half-height of 7.6 s neighboring peak is eluted 15 s later with W1⁄2 = 7.5 s. (a) Find out the resolution for these two components. (b) Is this resolution value good for quantitative analysis, why?
In molecular exclusion (size exclusion) chromatography, the molecules have the longest retention times. a) the larger molecules b) the smaller molecules
Which compound has a retention time of 1.5 minutes
Significant the IR peaks observed in each fraction? First image fraction #1 Second image fraction #2
SFC combines important advantages of gas and liquid chromatography. It is especially useful for analyzing compounds which cannot be determined using either GC or LC. Qualify the statement
A peak with a retention time of 10 minutes has a width at half-height of 7.6 s neighboring peak is eluted 15 s later with W½ = 7.5 s. (4) Find out the resolution for these two components. (a) (b) Is this resolution value good for quantitative analysis, why? (c) What difference in retention times is required for an adequate resolution of 1.5?
In a HPLC separation of two compounds, A and B, the retention times observed are 3.5 min. for A and 4.5 min. for B on a 15 cm column. The retention time for the mobile phase is 1.0 min. The peak widths (at the base) for A and B are 0.5 and 0.7 min respectively. Calculate the following: (i) The capacity factor of A and B. (ii) The peak resolution. (iii) The average number of theoretical plates in the column
Analysis of an unknown plant extract yield two peaks X and Y in a chromatogram, 15.65 and 17.03 min respectively in a 30.0 cm column. The peak base width for X is 1.06 and 1.15 for Y. The analysis gave a column resolution equal to?
Two components in an HPLC separation have retention times thatdiffer by 22 s. The first peak elutes in 10.5 min and the peakwidths are approximately equal. Use a spreadsheet to find theminimum number of theoretical plates needed to achieve thefollowing resolution, Rs, values: 0.50, 0.75, 0.90, 1.0, 1.10, 1.25,1.50, 1.75, 2.0, and 2.5. How would the results change if peak 2were twice as broad as peak 1?
(b) For column 1(i) What are the unadjusted retention times for components A and B?