Question 1 a) A resistor of 80 N resistance having a temperature coefficient of 0.0021 per degree C is to be constructed. Wires of two materials of suitable cross sectional area are available. For material A, the resistance 800 A B per 100metres and the temperature coefficient is 0.003 per degree C. For material B, the corresponding figures are 60 2 per 0.0015 per degree C. Calculate the suitable length of wires of materials A and B to be connected in series to construct the required resistor. All data are refried to the same temperature.

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter12: Electronic Control Devices
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Question 1
a) A resistor of 80 N resistance having a temperature coefficient of 0.0021 per
degree C is to be constructed. Wires of two materials of suitable cross sectional
area are available. For material A, the resistance 80n
per 100metres and the temperature coefficient is 0.003
per degree C. For material B, the corresponding figures
are 60 0 per 0.0015 per degree C. Calculate the suitable
length of wires of materials A and B to be connected in
series to construct the required resistor. All data are
refried to the same temperature.
A
B
Transcribed Image Text:Question 1 a) A resistor of 80 N resistance having a temperature coefficient of 0.0021 per degree C is to be constructed. Wires of two materials of suitable cross sectional area are available. For material A, the resistance 80n per 100metres and the temperature coefficient is 0.003 per degree C. For material B, the corresponding figures are 60 0 per 0.0015 per degree C. Calculate the suitable length of wires of materials A and B to be connected in series to construct the required resistor. All data are refried to the same temperature. A B
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