Question 1 6 p A spherical conductor has a radius of 8 mm and a charge of 20µC. Calculate the electric field at r = 6mm. O V/m 5 GV/m 2.815 GV/m 9 GV/m
Q: 1.0 m /20° 20° 1.0 m 3.0 g 3.0 g
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- 4. A charge q is placed in the cavity of a conductor as shown below. Will a charge outside the conductor experience an electric field due to the presence of q? 5. The conductor in the preceding figure has an excess charge of -5.0 µC. If a 2.0-µC point charge is placed in the cavity, what is the net charge on the surface of the cavity and on the outer surface of the conductor? Problems 6. Calculate the flux through the sheet of the previous problem if the plane of the sheet is at an angle of 60° to the field. Find the flux for both directions of the unit normal to the sheet.Determine the volume charge density, in pC/m3, at (3, -8, -2) if the electric field present in the region is E = sin (3 x + 2 y + 3 z) V/m. All coordinates are measured in meters.5. Given a charged cylinder of +10 µC, a diameter of 1.5 cm, and a length of 10 cm, solve for the following: 10 cm 1.5 cm a. Find the electric field outside of the cylinder. b. Find the electric field inside of the cylinder.
- Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rp has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = aer/ao + B/r + bo %3D where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: Vab = | S"Edr= - [ *Edr Calculating the antiderivative or indefinite integral, Vab = (-aage-r/ao + B + bo By definition, the capacitance C is related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (e-rb/ao - eralao) + B In( ) + bo ( ))A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108 C is placed on the plate. Find (a) the charge density on each face of the plate, (b) the electric field just above the plate, and (c) the electric field just below the plate. You may assume the charge density is uniform.1 ! 7 A skát с A spherically symmetric charge distribution produces the electric field E=( 5400 r²) N/C, where r is in m. Z mylabmastering.pearson.com/?courseld=12649908&key=55673220682936520262024#/ 2 pos W S X 3 20 F3 E D $ 4 C 888 R F What is the electric field strength at r= 16.0 cm ? Express your answer in newtons per coulomb. VG ΑΣΦ 4 Submit Part B Submit Part C What is the electric flux through a 32.0-cm-diameter spherical surface that is concentric with the charge distribution? Express your answer in newton meters squared per coulomb. ΕΠΙ ΑΣΦ % [VG| ΑΣΦ 5 Request Answer V FO Request Answer T How much charge is inside this 32.0-cm-diameter spherical surface? Express your answer in coulombs. G 4 a ^ 6 C 244 MacBook Air Y B SMC & ? 7 H ? N/C 80 F7 N-m²/C U C N H 8 - DII FS 1 ( 9 M DD K chegg.com X C ☆ O O MOSISO O 4 P
- Charge Q acts as a point charge to create an electric field. Its strength, measured a distance of 30 cm away, is 40 N/C. What would be the electric field strength ... a. 30 cm away from a source with charge 2Q? b. 30 cm away from a source with charge 3Q? c. 60 cm away from a source with charge 2Q?Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rp has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = ae-T/ao + B/r + bo where alpha (a), beta (8), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vah between the two conductors. The potential difference is related to the electric field by: Vab = Edr = - Edr Calculating the antiderivative or indefinite integral, Vab = (-aage-r/a0 + B + bo By definition, the capacitance Cis related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C= Q/( (e-rb/ao - eTalao) + B In( ) + bo ( ))A spherical shell with uniform volume charge density ρ = 1.84 nC/m3, inner radius a =10.0 cm, and outer radius b = 2.00a (Figure 5). What is the magnitude of the electricfield at radial distancesi. r = 0 ii. r = a/2.00 iii. r = a iv. r = 1.50a v. r = b vi. r = 3.00b
- Ex. 4: A metal sphere of radius 1 cm is charged with 3.14 u C. Find the electric intensity at a distance 1 m from centre of metal sphere.electrons radius r Two protons (p) and two (e) are arranged on a circle of 5 [cm], with angles 0₁ = 20°, 0₂ = 60°, 03 = 20° and 04 = 60°, as shown in the figure. (qp = +1.6 x 10-19 [C] and qe = -1.6 × 10-19 [C]). The figure is not to scale. 04 y a. Find Enet, the net electric field vector produced at the center of the circle. Enet = ([ ])i + ( ]) Ĵ [N/C] b. Where on the circle should a fifth point charge qo be placed (give its angle relative the +x-axis) and what is its value (calculate qo) in order to have Ēnet (the net electric field at the center of the circle) equals zero (Type the detailed solution to this question in the below box, Show all your calculation steps by typing in the box). P X1. Two thin conducting plates, each 30 cm on a side, are situated parallel to one another and 5 mm apart. If 1.3.10¹2 electrons are moved from one plate to the other, what is the electric field between the plates? (a) In your notebook, draw the two conducting plates and draw the electric field lines between the plates. How is the electric field directed? v (b) Calculate the surface charge density of the plates. C/m 0= (c) What is the electric field between the plates? E= N/C 2