Q8 ) A heat engine produces 200 kJ/s of mechanical power and operates at an efficiency of 40%. What would be the rate of heat rejection to the lower temperature heat sink in this case? a.300 kJ/s b.500 kJ/s c.150 kJ/s d.200 kJ/s e.50 kJ/s 8b) It is proposed to modify the heat engine in Q8 in such a way that it will now require exactly 200 kJ/s of heat to drive it. Which of the below “laws” would such a heat engine violate

Q8 ) A heat engine produces 200 kJ/s of mechanical power and operates at an efficiency of 40%. What would be the rate of heat rejection to the lower temperature heat sink in this case? a.300 kJ/s b.500 kJ/s c.150 kJ/s d.200 kJ/s e.50 kJ/s 8b) It is proposed to modify the heat engine in Q8 in such a way that it will now require exactly 200 kJ/s of heat to drive it. Which of the below “laws” would such a heat engine violate

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter44: Geothermal Heat Pumps

Section: Chapter Questions

Problem 13RQ: If 14 gpm of water is flowing through an open-loop heat pump with a temperature difference of 7F,...

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Q8 ) A heat engine produces 200 kJ/s of mechanical power and operates at an efficiency of 40%. What would be the rate of heat rejection to the lower temperature heat sink in this case? a.300 kJ/s b.500 kJ/s c.150 kJ/s d.200 kJ/s e.50 kJ/s
I. 1. During a cyclic process, a heat engine absorbs 500 J of heat from a hot reservoir, does work and ejects an amount of heat 300 J into the surroundings (cold reservoir). Calculate the efficiency of the heat engine?
A heat pump is used to heat a house. When the outside air temperature is 266K and the inside is maintained at 293K, the heat loss from the house is 195 kW. a. What is the minimum electric power (kW) required to operate the heat pump? b. What is the rate of heat transfer to the heat pump? C. What is the COP for an ideal heat pump operating between these temperatures?
SL-4 A reversible refrigerator is driven by a (non-reversible) heat engine with e-0.250. Both operate between two heat reservoirs at 300K and 450K. The power output of the engine is 5,000W, which is the entire power input to the refrigerator. a) Write down or calculate the magnitudes of the Wk, Qhe and Q. for one second of operation of the b) Write down or calculate the magnitudes of the Wk, Qn, and Q. for one second of operation of the refrigerator. c) Calculate the magnitudes of the Wkest, Qhnet, and Qenet for one second of operation of the system. d) Show on a diagram like the one above for problem SL-1 the energy flow for the engine and refrigerator individually on the left and the net energy flow for the engine-refrigerator system on the right. e) Does this net result violate the second law of thermodynamics? EXPLAIN your answes. 2.
A heat engine running between a pit at 15 degree and an energy storage that is 50 times warmer than the pitworks. 2/3 of the generated power is used to run the Carnot heat pump, which heats an home. Heatpump draws heat from the air at 4 degree and keeps the home at 15 degree. So the heat loss of homeis 61000 kJ / h;a. Describe the system by drawing it schematically.b. Calculate the minimum heat that should be transferred to the heat engine.
Refrigerationa.) Explain why you can’t cool down your kitchen by leaving your refrigerator or freezer door open with your refrigerator plugged in for an extended period of time.b.) The condenser of a home refrigerator is commonly underneath the appliance, thus the condensing refrigerant exchanges heat with household air, which averages 70oF. It is proposed toreconfigure a refrigerator so that the condenser is in the garage, where the average yearly temperature is about 50oF. Assume a freezer temperature of 0oF, a minimum temperature difference of 10K for heat transfer, and an actual coefficient of performance of 60% that of a Carnot cycle. Calculate the Coefficient of Performance for both configurations and discuss the pros and cons of this proposal.c.) Which is the most effective way to increase the coefficient of performance of a Carnot refrigerator: to increase TC with TH held constant or to decrease TH with TC held constant? Justify mathematically. For a real refrigerator, do…
Thermodynamics review that I cannot solve! Would appreciate some or all done out A heat engine with a thermal efficiency of 45% rejects 1000 kJ/kg of heat to a low temperature sink. 1. How much heat does it receive (kJ/kg)? 2. How much work does it produce (kJ/kg)? 3. If the cycle operates between temperatures of 400°C and 50°C,what is the maximum amount of work that this cycle can produce (kJ/kg)? 4. A Carnot heat pump operates between 273 K and 313 K, determine its Coefficient of Performance.
Consider the following: 1. Reverse heat engine 2. Main purpose of a machine is to heat up a space 3. Performance is measured with the help of Thermal Efficiency Which of the above condition relates with heat pump? Select one: O a. 2 and 3 only O b. 1 and 3 only O . 1, 2 and 3 O d. 1 and 2 only
Type: E 3. A heat pump is designed to transfer heat into a building at a temperature of 25°C and receive heat from underground at a temperature of 8°C. What is the maximum possible coefficient of performance of this heat pump?
Answer in half an hour I'll give good rating A heat engine produces 200 kJ/s of mechanical power and operates at an efficiency of 40%. What would be the rate of heat rejection to the lower temperature heat sink in this case? a. 300 kJ/s b. 500 kJ/s c. 150 kJ/s d. 200 kJ/s e. 50 kJ/s
Q-4 ) In a winter season when outside temperature is -4°C, the inside of house is to be maintained at 22°C. Estimate the minimum power required to run the heat pump of maintaining the temperature. Assume heating load as 150MJ/h.
A heat engine with efficiency - 60%, driving both a heat pump and refrigerator at the same time, the work generated by the heat engine (WHE=W₁+W₂) W₁ gose to heat pump which (COPH.P.= 2), and W₂ gose to Ref. From the Figure and missing 850 K Tmax =? Tmax=? values, Find: Qodd? a) The Qadd. Qrej, and Tmin of the Heat Pump. b) The Qadd. Qrej, and Tmax of the Heat Engine c) The Qrej. COPRef., and Tmax of the Refrigerator H.P. Tmin=? Qass=? W-150 K H.E. Qraj? 75 K W₂-50 K/ Redd 60 KJ Ref. 50 K