* :Q7/ The value of reaction RA is Point D 10 kN Point E h-200 mm 50 mm 2 kN 75 mm 2m 3m Point F b-100 mm * :Q8/ The value of reaction RB is Point D 10 kN Point E h-200 mm 50 mm 2 kN 75 mm 2m 3m Point F b-100 mm Q9/ The value of shear force (VA) at :the hinge A is Point D 10 kN Point E 50 mm h-200 mm 8 2 kN 75 mm Point F b-100 mm
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- Solve the preceding problem for the following data:P = 160 kN,JV = 200 tN,L = 2 m,b = 95 mm, h = 300 mm, and d = 200 mmRepeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.A polyethylene tube (length L) has a cap that when installed compresses a spring (with under-formed length L1) by an amount ?? = (L1 = L). Ignore deformations of the cap and base. Use the force at the base of the spring as the redundant. Use numerical properties given in the boxes. (a) What is the resulting Force-in the spring, Fk? (b) What is the resulting Force in the tube, Ftl (c) What is the filial length of the tube, Lf? (d) What temperature change ?T inside the tube will result in zero force in the spring
- A cargo ship is tied down to marine boll arts at a number of points along its length while its cargo is unloaded by a container handling crane. Each bollard is fastened to the wharf using anchor bolts. Three cables having known tension force magnitudes F, = ll0 kN.F, = 85kN.and F, 9OkNare secured to one bollard at a point A with coordinates (0.0.45 m. 0) in the x-r-: coordinate system shown in the figure part b. Each cable force is directed at an attachment point on the ship. Force F, is directed from point A to a point on the ship having coordinates (3 m, 9 m. 0) force F, is directed at a point with coordinates (6.5 m. 8.5 m. 2 m) and force F, is directed at a point with coordinates (8 m. 9 m. S m). The diameter of each anchor bolts is 4 24 mm. (a) Find the reaction forces and reaction moments at the base of the bollard. (b) Calculate the average shear stress in the anchor bolts (in the x-: plane). Assume each bolt cart ics an equal share of the total force.8:30 Test 3.pdf F1 F2 a CF3 A b a F4 D Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 = 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 = 10 kN; a = 30°, 0= 45° , B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 111.6 kN.m b) 112.6 kN.m e) - 184.6 kN.m d) - 109.6 kN.m e) - 104.1 kN.m 0 None of them 21 What is the resultant moment of the five forces acting on the rod about point B? a) -95.8 KN.m b) 42.7 kN.m c) 80.9 kN.m d) 10.9 kN.m e) 51.8 kN.m ) None of them 31 What is the resultant moment of the five forces acting on the rod about point C? b) - 21.1 kN.m e) 17.4 kN.m d) - 16.5 kN.m e) 15.6 kN.m ) None of them a) 32.6 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 37.6 kN.m b) 73.8 kN.m c) 71.6 kN.m d) 52.1 kN.m e) 21.1 kN.m ) None of them 5] What is the moment of the force F2 about point E? a) 90.7 kN.m b) - 88.1 kN.m c) 54.6 kN.m d) 103.1 kN.m e) 100.7 kN.m ) None…The linkage shown is used in a vehicle suspension system. Find the forces indicated below when a static force of F = 820 lb is applied to the tire at point C at an angle of 0 = 22° as shown. Assume the connection of the wheel to member AB is rigid. hs hy hi F BY NC SA W4. W, Ws 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value Variable Value hi 10 in Wi 8.8 in h2 15.6 in W2 5.6 in h3 18.1 in W3 10.8 in h4 10.9 in WĄ 7.4 in h5 4.9 in W5 9.3 in For all answers, take x as positive to the right and y as positive upward. At point B, member AB exerts a force of B = j lbs on member BHE. At point A, member AD exerts a force of A + j lbs on member AB. At point H, shock GH exerts a force of H = i + i lbs on member ВНЕ. At point E, the magnitude of the force exerted on the car body by member BHE is lbs. At point D, the magnitude of the force exerted on the car body by member AD is lbs. At point G, the…
- Member AB (helical spring) and Member AC (axial rod) are carrying a weight at point A. Member AB has the following properties: R = 90 mm, n -4 turns, G- 70 GPa, d- 30 mm, and Talow = 105 MPa while Member AC has the following properties: L= 2.A- 500 mm?, E = 200 GPa, and a low- 30 MPa. Determine the maximum safe %3D value of W (in N). Use simplified formula for the helical spring. A 60°5 - note: ignore weight of the bar.A) ( - 6/7)T(CB) + A(y)=0 (A=reaction force at A, A(x), A(y), A(z) are components of force A)B) (2/7)T(CB)+A(x)=392 (A=reaction force at A, A(x), A(y), A(z) are components of force A)C) A(x)=2A(y) (A=reaction force at A, A(x), A(y), A(z) are components of force A)D) A(x)=5A(z) (A=reaction force at A,A(x), A(y), A(z) are components of force A)%w,, 4 Q1: MO =S 400 lb F = 400 i F2 = -600 k F3 = 500 sin 45 i -500 cos 45 k 3 7" Y600 Ib M- rįxF,, M,- 12x F, M,- r3x F, M-M, + M, + M, 500 lb 2 w: * 1.5 m P= 0.8 kN T-1.2 kN 3m Determine the x-, y-, and z- components of T. Determine the angles which the line of action of T formms with the positive x-, y-, and z-axes. Calculate the projection of P onto a line between A and Fand determine the angle between P and AF Determine the vector expression for the moment of P about point E. 1, élo Lel
- 4- Determine the horizontal displacement at the point C (Aca) and vertical displacement at the point B (A.) for the loaded frame shown below using Castigliano's first theorem method assuming (EI is constant). 10 k 18 fi- 20 k B 18 ft- 10 k 15 ftValne Parameter Whmade Shear Stress o Spring wire Modulus e ngidity e.SRing Smng Coil haanal chometes Deflection of Spring at allowable Shoar Stress Factor of Safe Wahl's shear Stress factor 800MPA 9AKN/mmf Wire 25mm 15mm K= HC-1+0:615 4C-4 Using he hafurmaton m table 1, desana helical Compresion Spring by detemindng; 9) Allowable Axial loudw turns n' of b) Actve numberWhich set of compatibility equations matches the following torsion members connected end-to-end in series? 30 in. O || = C a 560 8₁ a & + gap 05/0 18 in. 6 in. (2) 0 & + ₂ = 0 О ф, = фг 0 8₁ = 8₂ - 8₂ 04+₂=0 & + ₂ = constant Ta (3) 8₁ + gap = 8₂ &₁ = & + gap D. & + ₂ = constant 8 in. (2)