TRANSCRIBE THE FOLLOWING SOLUTION IN DIGITAL FORMAT b) TangentsFor tangentD=c) otherdistance from center to line = 2| 1-3K-31√K²+113 K+2)√K²+= 2(3K+²²= 2² (K²+1)9 +²+4+ 12k = 4*2+4+= 25K² + 12x = 0K=0, K = -1.-12-+K ε (-∞, -1²/²-) u (0,00) álla)equation of circle(x-3)² +)2x2+y2 -6x-2y +6=0(y-1)² = 4Су-1)2circle with centery =Kx +3lineInteresect at two point if distance fromcenter is less than 2Let D denote distance3K-3/Sk2+1(3,1)radius = 2D = |3K+2/√K²+1|3K+21√K²4T| 3K+2) < 2 √ K²+1(3k+232 с иск2+1)9к2+4+12k < 4к2+225K² +12K

Note: As per your request, the solution is in digital format is given below. Q4. Equation of…

Q4. equation of circle x² + y² - 6x-2y +6 = 0 2 )2 (x-3)² + (y-13² = 4 circle with center line y = Interesect at two Kx +3 at two point if distance from center is less than 2 Let D denote distance 1 3 K -3 √K ²+1 D = |3K+2) к2+1 |3K+21 √K²+T (3,1) 22 + radius = 2 | 3 K+2 | < 2 √ K³² (3k+232 с иск2+1) 4x² gx²+4+12K < 2 5K² +12K