Q4: A Company requires a stainless steel that is tough enough for use in the Tropics(50 °C) as well as the Arctic (-50 °C). They peruse the data in Figure 1 below. At thedesigned use stress, the component can tolerate a surface defect of 0.080 in. at 50 °C.Manufacturing inspection equipment can only detect defects that are larger than0.050 in. Will a fracture unsaąfe situation arise at -50 °C for the same loading,explain why?1801802001200160160-1601000140140120Yield strengthB001203120100100600808040060Fracturetoughness402002020Figure 101150-150-100-5050100Testing temperature (°C)Fracture toughness (Hsi-in.12)60Fracture toughness (MPa-m)Yield strength (MPa)우Yield strength (ksi)

Given: A Company requires a stainless steel that is tough enough for use in the Tropic (50 °C) as…

Q4: A Company requires a stainless steel that is tough enöügh (50 °C) as well as the Arctic (-50 °C). They peruse the data in Figure 1 below. At the- designed use stress, the component can tolerate a surface defect of 0.080 in. at 50 °C. Manufacturing inspection equipment can only detect defects that are larger than 0.050 in. Will a fracture unsafe situation arise at -50 °C for the same loading- explain why? " 180 200 180 1200 160 160 160 1000 140 140 Yleld strength 3120 120 800 120 100 100 600 등 180 80 80 400 60 Fracture toughness 40 200 20 40 40 20 Figure 1 -150 0 50 -100 -50 100 150 Testing temperature (°C) Fracture toughness si-in. ) Fracture toughness (MPa-m) Yield strength (MPa) (S) yibuans pjaA

Q4: A Company requires a stainless steel that is tough enöügh (50 °C) as well as the Arctic (-50 °C). They peruse the data in Figure 1 below. At the- designed use stress, the component can tolerate a surface defect of 0.080 in. at 50 °C. Manufacturing inspection equipment can only detect defects that are larger than 0.050 in. Will a fracture unsafe situation arise at -50 °C for the same loading- explain why? " 180 200 180 1200 160 160 160 1000 140 140 Yleld strength 3120 120 800 120 100 100 600 등 180 80 80 400 60 Fracture toughness 40 200 20 40 40 20 Figure 1 -150 0 50 -100 -50 100 150 Testing temperature (°C) Fracture toughness si-in. ) Fracture toughness (MPa-m) Yield strength (MPa) (S) yibuans pjaA

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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ASAP
Steel subject to tensile stress of 1030 MPa, it has K1c of 54.8 MPa(m) – a handbook value If it has a ‘largest surface crack’ .5 mm (.0005 m) long will it grow and fracture? What crack size will result in failure?
Question 6 What is the calculated fracture toughness, K, for the perspex specimen in MPa root m? Give your answer to 2 decimal places. P = 250 N, crack length = 5.5 mm W= 13.3 mm, B = 5.45 mm Note that the span length (s) is 38mm. Take f(a/W) as 0.78
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Consider the tensile stress-strain diagram below. If samples 1 and 2 are identical except that they were tested at different temperatures, which sample was tested at a lower temperature? Note: This question will be marked negatively so consider your answer carefully. A. Sample 1 B. Both were tested at the same temperature/ Alby is by die dieselfde temperatuur getoets C. Sample 2
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Part B The stress-strain diagram for a steel alloy having an original diameter of 1.0 in. and a gage length of 7 in. is shown in the figure below. (Eigure 1) Determine the load on the specimen that causes yielding. Express your answer to three significant figures and include appropriate units. HA Py- Value Units Submit Request Answer Part C Figure t oft> Determine the ultimate load the specimen will support. Express your answer to three significant figures and include appropriate units. NO 70 60 50 P. - Value Units 40 30 20 Submit Bequest Answer 10 (in/in) o G04 0m 12 016 020 024 02 a aa omams Provide Feedback
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