Q2/ If you have the following matrix A= 1 2 3 4 56 7 8 9 10 11 12 13 14 15 16 Write one command that do the following action: (answer two only) 1- A= 0 0 0 6 0 0 10 11 0 1 5 13 14 15 16 2- A= 9 10 11 12 3- A= 2 3 4 15 9 13 5 6 7 8 26 10 14 9 10 11 12 37 11 15 1 13 14 15 16 48 12 16
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- You have been asked to store the IDs and scores of competitors in three rounds of a game and find out total score of each and print the ID of winner who is having maximum score. Following is the data: Using eclipse ID Score 1 Score 2 Score 3 123 23 12 24 234 34 10 32 345 12 34 21 456 10 23 21 567 10 19 23Please modify the code below for "Current Date" ********************************************************************** from pandas_datareader import data as pdrimport yfinance as yfin # Work around until# pandas_datareader is fixed.import datetimeimport pandas as pdimport matplotlib.pyplot as pltimport numpy as np# Show all columns.pd.set_option('display.max_columns', None)pd.set_option('display.width', 1000)def getStock(stk, numDays):print(stk)# Only gets up until day before during# trading hoursdt = datetime.date.today()# For some reason, must add 1 day to get current stock prices# during trade hours. (Prices are about 15 min behind actual prices.)dtNow = dt + datetime.timedelta(days=1)dtNowStr = dtNow.strftime("%Y-%m-%d")dtPast = dt + datetime.timedelta(days=-numDays)dtPastStr = dtPast.strftime("%Y-%m-%d")yfin.pdr_override()df = pdr.get_data_yahoo(stk, start=dtPastStr, end=dtNowStr)return df################################################################### CONFIGURATION…* The command (fprintf ) is used to control the number of decimal .digits True O False O (2) * The command (interp2 ) is used in two dimensional interpolation to increase the number of divisions of the x .and y mesh True O False نقطتان (2)
- Complete the following function according to its docstring. def check_password_exclusive(passwd: str) -> bool: """ An exclusive strong password has a length greater than or equal to 6, and contains ONLY letters and numbers. Return True if and only if passwd is considered an exclusive strong password. >>> check_password_exclusive('I<3csc108!') False >>> check_password_exclusive('time2sleep4me') True """Consider the following code snippet, which uses the AddThree procedure defined below: .data sum BYTE ? .code mov eax, 11 mov edx, 10 mov esi, 1 call AddThree mov sum, eax AddThree PROC push edx push esi add edx, esi add eax, edx pop esi pop edx ret AddThree ENDP Which of the following are the arguments (input parameters) for this procedure? (Select all that apply) edx sum eax O esiHAHAAAAAAHN HNM1000 OHNM 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 27 28 30 31 32 section . data .section .text .globl _start start: pushq $4 pushq $3 call function-A addq $16, $rsp movg %rax, %rbx movq $1, rax int $0x80 .type function-A, @function function-A: pushq rbp movq rsp, rbp. subq $8, rsp movg 16(%rbp), %rbx movq 24 (rbp), rcx movg %rbx, -8(%rbp) label-A: #variable y #variable z cmpq $1, $rcx je label-B movq -8 (&rbp), rax imulg %rbx, srax movq krax, -8 (%rbp) decq rcx jmp label-A label-B: movq -8 (Srbp), rax movq rbp, rsp popq &rbp ret
- HAHAAAAAAHN HNM1000 OHNM 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 27 28 30 31 32 section . data .section .text .globl _start start: pushq $4 pushq $3 call function-A addq $16, $rsp movg %rax, %rbx movq $1, rax int $0x80 .type function-A, @function function-A: pushq Srbp movq rsp, rbp. subq $8, rsp mova 16 (%rbp), rbx movg 24 (rbp), rcx mova Srbx, -8 (Srbp) label-A: #variable y #variable z cmpq $1, $rcx je label-B movq -8 (&rbp), rax imulg %rbx, srax movq rax, -8 (%rbp) decq rcx jmp label-A label-B: movq8 (rbp), rax movq rbp, rsp popq &rbp retHAHAAAAAAHN HNM1000 OHNM 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 27 28 30 31 32 section . data .section .text .globl _start start: pushq $4 pushq $3 call function-A addq $16, $rsp movg %rax, %rbx movq $1, rax int $0x80 .type function-A, @function function-A: pushq rbp movq rsp, rbp. subq $8, rsp movg 16(%rbp), %rbx movq 24 (rbp), rcx movg %rbx, -8(%rbp) label-A: #variable y #variable z cmpq $1, $rcx je label-B movq -8 (&rbp), rax imulg %rbx, srax movq rax, -8 (%rbp) decq rcx jmp label-A label-B: movq -8 (Srbp), rax movq rbp, rsp popq &rbp ret1. Write an order to generate binomial data with the number of observations (n) being 50, the number of trials (size) being 5 and the probability of success being 0.5, then storing the results in the binomial data matrix, with the number of columns being 5. 2. Write an R statement to determine a number in the range 1 to 10 is odd or even. Use loop statements and is statements.
- HAHAAAAAAHN HNM1000 OHNM 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 27 28 30 31 32 section . data .section .text .globl _start start: pushq $4 pushq $3 call function-A addq $16, $rsp movg %rax, %rbx movq $1, rax int $0x80 .type function-A, @function function-A: pushq Srbp movą rsp, rbp. subq $8, rsp movg 16(%rbp), %rbx movq 24 (rbp), rcx movg %rbx, -8(%rbp) label-A: #variable y #variable z cmpq $1, $rcx je label-B movq -8 (&rbp), rax imulg %rbx, srax movq rax, -8 (%rbp) decq rcx jmp label-A label-B: movq -8 (Srbp), rax mova Srbp, rsp popq &rbp retTwo friends are exchanging messages through regular post mail. They don't want anyone to understand their messages in case anyone read them. The messages are in the form of an array of characters, where each character has a numeric value as illustrated in the below lookup table. GHIJ K LM 6 7 8 A BC DE F 1 2 3 4 9 10 11 12 13 QRS 14 15 16 17 18 19 20 N O P T U v V w X Y 21 22 23 24 25 26 They decided to change the characters in the array in a way that cannot be observed by any accidental reading. They do so as follows: 1- Given the original message, for example: GREETINGS 2- transform the original character to its numeric value 7 18 5 5 20 9 14 7 19 3- For each number, subtracting from its value the value of the first lower value character after it, and if there's no such character they will keep that character without any change. 2 12 5 5 11 2 77 19In the given code below we want to swap a and b. b- Fix the code by using blocking assignment only. c- Fix the code by using non-blocking assignment only. The code: always @(posedge clk) begin a=b; b=a; end