Q2-3/ An agricultural farm is cultivated by crops. Available data are:dr = 1.2 (m), A = 50 (Hectare), G=1.35, Gs=2.7.and (wy)% = 15%.¿Compute values of (dw)FANSWER/(Wv)s=50%, (wv)d = 15%, (Wv)F = 35%(dw)F= 0.42 (m of water depth/ one Irrigation process).

To compute the field capacity (wv)F.(wv)F = (wv)s - (wv)dwhere:(wv)s is the saturation water…

Q2-3/ An agricultural farm is cultivated by crops. Available data are: dr = 1.2 (m), A = 50 (Hectare), G= 1.35, G, = 2.7 .and (wy)% = 15%. ¿Compute values of (dw)F ANSWER/ (Wv)s=50%, (wv)d = 15%, (Wv)F = 35% (dw)F= 0.42 (m of water depth/ one Irrigation process).

Q2-3/ An agricultural farm is cultivated by crops. Available data are: dr = 1.2 (m), A = 50 (Hectare), G= 1.35, G, = 2.7 .and (wy)% = 15%. ¿Compute values of (dw)F ANSWER/ (Wv)s=50%, (wv)d = 15%, (Wv)F = 35% (dw)F= 0.42 (m of water depth/ one Irrigation process).

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Q2-3/ An agricultural farm is cultivated by crops. Available data are:
dr = 1.2 (m), A = 50 (Hectare), G=1.35, Gs=2.7.and (wy)% = 15%.
¿Compute values of (dw)F
ANSWER/
(Wv)s=50%, (wv)d = 15%, (Wv)F = 35%
(dw)F= 0.42 (m of water depth/ one Irrigation process).

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