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- 1- The "divergence grad 6" can be written as: a: V(V.) b: Vx(V) e: V.(V.) d: V.(V) 2-The acceleration vector in plane polar coordinates is a = (-ro?)e, +(rö + 2ró)eo If a particle moves on a circle path with constant radius b then the radial and transverse components respectively are: a: be and bö b: b and 2bė e: B - bộ and zero d: zero and b- bo? 3- The concept of impulse can be obtained if the force is: a: F(x) b: F(t) e: F(v) d: constant 4- The position vector of a particle can be written in cylindrical coordinates (R, . z) as: a: r=ReR b: r-R eg +o e, + Ze, e: r=R eg +Ze, d: r=ReR + e,A car P travels along a straight road with a constant speed v-76 mi/hr. At the instant when the angle 0-46°, determine the values of in ft/sec and 0 in deg/sec. Assume - 106. Answers: 0- 1011 ft/sec deg/secThe piston of the hydraulic cylinder gives pin A a constant velocity v = 2.1 ft/sec in the direction shown for an interval of its motion. For where r = OA. the instant when = 54%, determine , r, 0, and 6.1" ✓ Answers: r = r = 0 = ÿ = i -1.6989 i 1.9645 i 2.425 10.623 ft/sec ft/sec² rad/sec rad/sec²
- Given: A boat travels around a circular path, p= 40 m, at a speed that increases with time, v = (0.0625 t2) m/s. v30.06252 40 m Find: The magnitudes of the boat's velocity and acceleration at the instant t = 10 s.4. 2) The hydraulic cylinder D extends, moves the rigid rod ABC, and causes the collar A to move with velocity and acceleration both to the left. If the dimensions 4 1.0 ft, and 2 = 1.7 ft, VA = 4.9 ft/s, aa = 2.6 ft/s2, and the angle 0 = 27°, determine the speed of point B. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper unit. В 12 D a Your Answer: Answer units 1,Applying principles of dynamics, with step by step solutions pls (i give 5 stars) A freighter is moving at a speed of 8 nautical miles per hour. The engines then had to be suddenly stopped. If it takes 10 minutes for the freighter to reduce its speed to 3 knots, determine the distance moved by the ship and its speed at the end of this interval. The deceleration of the ship is propor-tional to the square of its speed such that a = -kV^2.
- Find the distance covered by object A in 10 seconds . Its initial velocity V1 = 15 m/s and its acceleration 2 m/s2 : You can use the formulae V2 - V1 = at V22 - V,² = 2 a s S = V, t + 0.5 a t2 :Choose the correct answer :Select one a. 250 m b. 30 m c. 1800 m d. 450 mThe x-coordinate of a particle in curvilinear motion is given by x = 3.8t3 - 2.6t where x is in feet and t is in seconds. The y-component of acceleration in feet per second squared is given by ay = 3.9t. If the particle has y-components y = 0 and vy = 5.2 ft/sec whent = 0, find %3D %3D the magnitudes of the velocity v and acceleration a when t = 5.3 sec. Sketch the path for the first 5.3 seconds of motion, and show the velocity and acceleration vectors for t = 5.3 sec. Answers: V = i ft/sec a = ft/sec2M, 1)Write the time derivative of the usual basis vectors in polar coordinates in terms of ø. Use these relation to compute the acceleration of a point mass (in vector form). Find kinetic energy of point mass m in polar coordinates. 2)In the figure above the pulley and mass m2 form a pendulum of variable length. Size of mass m2 is so small that it can be treated as a point mass. Initially mass mi is at y=0 and length of the pendulum is Lo and angle ø =n/3. Initial velocities are zero. At the instant mass m, reaches y= Lo/4 the angle Ø = n |4 the angular velocity is measured as 2rad/sec. What is time derivative of the length of the pendulum (the rope slides over the pulley without friction, rope is massless) 3) Find accelerations for ø = n/4
- Two radio transmitters positioned 400 mi apart along the shore send simultaneous signals to a ship that is 200 mi offshore and sailing parallel to the shoreline. The signal from transmitter S reaches the ship 200 microseconds later than the signal from transmitter T. The signals travel at a speed of 186,000 miles per second, or 0.186 mile per microsecond. Find the equation of the hyperbola with foci S and T on which the ship is located. (Hint: For any point on the hyperbola, the absolute value of the difference of its distances from the foci is 2a.) 200 mi Help me solve this C 400 mi Assume the origin is located at the midpoint of the foci. What is the equation of the hyperbola with foci S and I on which the ship is located? (Simplify your answer. Type your answer in standard form.) View an example Get more help. Ship Clear all Skill builder Check answer orreAn automobile P is traveling along a circular track of radius R=958.4 m. At position "A" on the track, the automobile has a speed of UA = 10.3 m/s. At this position, the driver of the automobile applies the brakes causing the speed of the automobile to change with distance s traveled along the track according to the following equation: U(S) = VA COS(0.001s) m/s (cos is in radians), where s is given in meters. Determine the magnitude of the acceleration for the driver when the automobile reaches position "B" on the track where "B" is a quarter of the distance around the track from position "A". R B O circular trackSHOW THE SOLUTION: One morning, Connie walks from her house to go to a store that is 500 ft, S 40o W from her house. She starts walking 120 ft, SW; then continues walking 100 ft, 10o S of E; then sees a friend who is 700 ft, 30o N of E from where she is. What is her friend’s location, (magnitude and direction) relative to her house? (Answer: 667.54 ft, 21.79o N of E) From her friend’s location, how far and in what direction should Connie walk to finally get to the store? (Answer: 1133.08 ft, 33.83o S of W)