Q 27.25: The circuit below has three resistors. If the circuit has a 3 volt battery, what is the current through R₁? R₁ = 2 ohms, R₂ = 0.5 ohm, R3 = 3 ohm +4 R₁ R₂ R₂
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- What is the voltage between points a andb (AVab = Vb-Va) if R1 = 4.00 Q, R2 and R3 are unknown, R4=8.00 Q and R5=D4.00 Q, the equivalent resistance of the circuit is 7.34 2, and ɛ = 7.00 V. Pay %3D attention to the sign!A circuit made up of 6 resistors is shown in the figure, with resistances R1 =11 Q, R2 = 45 N, R3 = 45 Q, R4 = 52 Q, R5 = 89 N, and R6= 38 Q. The total current going through the circuit is I= 3.5 A. R, RA a R R2 R. b 1. Calculate the value of AV, in volts.Problem 4: A current of I = 2.3 A passes through the circuit shown, where R = 95 Q. I 3R 5R ww ww 2R 6R 2R 7R ww ww 10R 5R Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the source, V. Expression : V = Select from the variables below to write your expression. Note that all variables may not be required. a, B, 0, a, d, g, h, I, j, k, m, P, R, S, t Part (b) What is the voltage, Vin volts? Numeric : A numeric value is expected and not an expression. V =
- A cell of em.f. 2V and external resistance 0.5 Q is connected across a resistor (R). The current that flows is same as that, when a cell of e.m.f. 1.5 V and external resistance 0.3 Q is connected across the same resistor. Then R=03Q (b) R=0.60 R=05Q (d) R=0.75 92Refer to the given circuit. C1 = 5 µF C3 = 8 µF C2 = 4 µF C4 = 6 µF Cs = 4 µF DURACELL VT = 12 V Compute for the total energy of the entire circuit. Select one: a. 128.42 micro Joules O b. 352.12 micro Joules О. 273.56 micro Joules O d. 478.08 micro JoulesQ1(a) For the dc network shown in Figure Q1 (a), calculate the following: i. The total resistance Rr as seen by the source i. The total current I i. The voltage across the resistance R4 R3 20 + I R: R4 8Ω V. R5 E 24V 120 Rs 12Ω Figure Q1 (a)
- Given a parallel circuit with three resistors and a total voltage of 15, R1 = 10 2, R2 = 20 2, and R3 = 30 Q. %3D %3D Find the 13.Three resistors with resistances R1 = 0.37 ohm, R2 = 6.59 ohm, and R3 = 7.36 ohm are is series circuit with a 13.9 volt battery. What is the potential (volt) across the R2 resistor?You have a circuit consisting of a power supply, switch, resistor, two capacitors, and voltage/current probes. The resistor has the value R1 = (1.8 ± 10%) MQ. The capacitors have %3D the values C1 = (0.6 ± 20%) µF and C2 = (2.2 ± 20%) µF. The logger pro data resembles the plot below. 40 35 30 25 20 15 10 1 2 3 5 6 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 a) Label the title and all the axes on the plot above. Identify which region corresponds to the capacitors charging and discharging. Be sure to include appropriate units (MKS).
- A battery provides a voltage of 10.0 V and has unknown internal resistance Rnt. When the battery is connected across a resistor of resistance R = 9.00 2, the current in the circuit is I = 1.00 A. (Figure 1) Figure < 1 of 1 R. int %3DIn the circuit pictured, the resistors have values of R =170 N, R2 = 62 N, and R3 = 130 Q, and the battery has an emf ɛ = 274 V. (a) How much current ibatt, in amperes, goes through the battery? (b) What is the current i2, in amperes, through resistor R2? R R3Consider the circuit below. The battery has an open-circuit voltage of ɛ = 30 V and an internal resistance ofr = 1N. R2 = 18.00 N E = 30.00 V R1 9.00 N %3D ir = 1.00 N R3 10.00 N R5 8.00 N R4 = 10.00 N Hint a. Find the equivalent resistance of the circuit (not including the internal resistance). Reg b. Find the current out of the battery (do not ignore the internal resistance). Ibat A c. Find the potential drop across each resistor. o Across Rj and R2: AV = V. Across R3 and R4: AV = V. Across Rs: Д V — V. Across r: AV = V. (These drops should add up to the value of ɛ.) d. Find the currents through Rị and R2: IRI A IR2 A e. Find the currents through R3 and R4: IR3 А IRA A f. What is the percentage of the total power supplied by the battery that is dissipated in the internal resistance of the battery? A total of % of the total power supplied by the battery is dissipated in the internal resistance r. 十