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- a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?Create an iterator that returns numbers, starting with 1, and each sequence will increase by one (returning 1,2,3,4,5 etc.):import randomdef heads_or_tails(n): i=0 n = 'n' while i<n: num = random.randint(0,1) if num==0: print('heads') else: print('tails') i+=1 if __name__ == '__main__': random.seed(1) number_of_flips = int(input()) heads_or_tails(number_of_flips) it says Traceback (most recent call last): File "main.py", line 16, in <module> heads_or_tails(number_of_flips) File "main.py", line 5, in heads_or_tails while i<n: TypeError: '<' not supported between instances of 'int' and 'str'
- Java - Encapsulation Create a class Point with attributes x and y which are both integers. Create getters and setters for these attributes and implement the following methods: 1. calculateDistance() - calculates the distance from the origin to the point. Returns a double, formula is sqrt(x^2 + y^2) 2. printCoordinates() - prints "(x,y)" Ask for user inputs for x and y. Use the methods printCoordinates() and calculateDistance() respectively. Inputs 1. X 2. Y Sample Output Enter x: 20 Enter y: 15 (20,15) 25.00Complete the drawTriangle() function in script.js that draws a triangle with asterisks (*) based on the triangleSize parameter. Ex: drawTriangle(4) outputs to the console a triangle with triangleSize 4, so the longest side (4 asterisks) appears on the bottom line: * ** *** **** Hint: Use a loop inside a loop to complete drawTriangle(). The outer loop is responsible for outputting each asterisk line, and the inner loop is responsible for building the asterisk line with the appropriate length by concatenating asterisks to a single string. To test the JavaScript in your web browser, call drawTriangle() from the JavaScript console.please name this cards.py. You may use the following code in your program: import random SUITS = "♠ ♡ ♢ ♣".split()RANKS = "2 3 4 5 6 7 8 9 10 J Q K A".split() def create_deck(shuffle=False): """Create a new deck of 52 cards""" deck = [(s, r) for r in RANKS for s in SUITS] if shuffle: random.shuffle(deck) return deck This code creates a random deck of cards (each card is a tuple consisting of a rank and suit). You are to ask the user how many 5-card hands to play and will keep track of the following poker hands. You will need to reshuffle the deck as many times as necessary to get the required number of hands. An example run of the program is as follows. Enter the number of hands to deal: 10000Hand % of Hands Hands of Type2 of a kind 41.290% 4129 3 of a kind 1.970% 197 4 of a kind 0.010% 1 2 pair 4.860% 486 Full house 0.150% 15 Flush 0.220% 22 If you deal enough…
- strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside down). Find all strobogrammatic numbers that are of length = n. For example, Given n = 2, return ["11","69","88","96"]. def gen_strobogrammatic(n): Given n, generate all strobogrammatic numbers of length n. :type n: int :rtype: List[str] return helper(n, n) def helper(n, length): if n == 0: return [™"] if n == 1: return ["1", "0", "8"] middles = helper(n-2, length) result = [] for middle in middles: if n != length: result.append("0" + middle + "0") result.append("8" + middle + "8") result.append("1" + middle + "1") result.append("9" + middle + "6") result.append("6" + middle + "9") return result def strobogrammatic_in_range(low, high): :type low: str :type high: str :rtype: int res = count = 0 low_len = len(low) high_len = len(high) for i in range(low_len, high_len + 1): res.extend(helper2(i, i)) for perm in res: if len(perm) == low_len and int(perm) int(high): continue count += 1 return…def findOccurrences(s, ch): lst = [] for i in range(0, len(s)): if a==s[i]: lst.append(i) return lst Use the code above instead of enumerate in the code posted below. n=int(input("Number of rounds of Hangman to be played:")) for i in range(0,n): word = input("welcome!") guesses = '' turns = int(input("Enter the number of failed attempts allowed:")) def hangman(word): secrete_word = "-" * len(word) print(" the secrete word " + secrete_word) user_input = input("Guess a letter: ") if user_input in word: occurences = findOccurrences(word, user_input) for index in occurences: secrete_word = secrete_word[:index] + user_input + secrete_word[index + 1:] print(secrete_word) else: user_input = input("Sorry that letter was not found, please try again: ") def findOccurrences(s, ch): return [i for i, letter in enumerate(s) if letter == ch] *** enumerate not discussed in…public void OnSend(View v){ String phoneNumber = number.getText().toString(); String smsmessage = message.getText().toString(); if(phoneNumber == null || phoneNumber.length() == 0 || smsmessage == null || smsmessage.length() == 0){ return; } if(checkPermission(Manifest.permission.SEND_SMS)){ SmsManager smsManager = SmsManager.getDefault(); smsManager.sendTextMessage(phoneNumber, null, smsmessage, null, null); Toast.makeText(this, "Message sent", Toast.LENGTH_SHORT).show(); } Question 2: Explain the following code: button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { FragmentManager fm = getSupportFragmentManager(); FragmentTransaction ft = fm.beginTransaction(); XFragment xfragment = new XFragment(); ft.add(R.id.Main_fragment, xfragment);…
- int binsearch (int X , int V [] , int n ) { int low , high , mid , i ; low = 0; high = n - 1; for ( i = 0; i < high ; i ++) { if( V[ i ] > V [ i +1]) return -2; } while ( low <= high ) { mid = ( low + high )/2; if ( X < V [ mid ]) high = mid - 1; else if ( X > V [ mid ]) low = mid + 1; else return mid ; } return -1; } This code takes as input a sorted array V of size n, and an integer X, if X exists in the array it will return the index of X, else it will return -1. 1. Draw a CFG for binsearch(). 2. From the CFG, identify a set of entry–exit paths to satisfy the complete statement coverage criterion. 3. Identify additional paths, if necessary, to satisfy the complete branch coverage criterion. 4. For each path identified above, derive their path predicate…import numpy as np import torch import matplotlib.pyplot as plt Quiz Preparation Question 1. Write a function that generates a random tensor of n x n (n is the input). The output is the mean of the tensor. = 2, 4, 8, 16, ... 1024 and generate a vector 2. Write a code (for loop) that call that calls the function above with n = M(n). Plot the vector as a function of the log of n. 3. Given an n x m array write a code that replaces every element that is larger than 0.5 with 0.5. 4. The second derivative of a function can be approximated by the finite difference 1 ƒ"(x₂) = 73 (ƒ(£;+1) — 2ƒ(x;) + f(x;-1)) Given a vector f with values f = [f(xo),..., f(n) write a code that computes the approximation to f"(x) 5. The power method is a method to compute the largest eigenvalue of a matrix. Your google search is using this method every time you perform a google search. The method consists of the iteration Vj+1 = Av; || Avi|| where v; is a vector with chosen as a random vector, and A is the matrix…using System;using System.Text.RegularExpressions;class chapter8 {static void Main() {string words = "08/14/57 46 02/25/59 45 06/05/85 18" +"03/12/88 16 09/09/90 13";string regExp1 = "(\\s\\d{2}\\s)";MatchCollection matchSet = Regex.Matches(words,regExp1);foreach (Match aMatch in matchSet)Console.WriteLine(aMatch.Groups[0].Captures[0]);}} Now let’s modify this program to search for dates instead of ages, and usea grouping construct to organize the dates. And write the c# code: