public static void remove (double array[], int indexToRemove) { for (int i indexToRemove; i < sizeArray; i++) { //fill in here } return; }
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(Java)
question 3
choose the correct multiple choice
![Complete the following method to remove a value from an array:
public static void remove (double array[], int
indexToRemove) {
for (int i
indexToRemove; i < sizeArray; i++) {
//fill in here
}
return;
}
O array[i - 1] = array[i];
%3D
O array[i] = array[i - 1];
O array[i + 1] = array[i];
O array[i] = array[i + 1];
O array[i]++;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcba87776-bc0e-4a22-82e3-068a63784e86%2F60f8e053-76f3-4cac-9de0-1a96c995afb4%2Fcsxhu4_processed.png&w=3840&q=75)
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- void changeAll(int x[]) { x[0] = x[0] + 5; return; The first element in an array would be increased by 5 The array would be the same because it was passed by value x would be increased by 5 All the elements in the passed array would be incremented by 51- fillArray_1D() method, to initialize the 1D array with random values (between 0 and 99) void fillArray_1D(int array[], int size) { for(int i = 0; i < size; i++) { array[i] =(rand() % 100); } } • fillArray_2D() method, to initialize the 2-D array with random values (between 0 and 99). For the sake of simplicity, assume the 2D array size is always [3][3]. void fillArray_1D(int array[3][4]) { for(int i = 0; i < 3; i++) { for(int j = 0; j < 3; i++) { } } } array[i][j] = (rand() % 100); 2- printArray_1D () method, to display 1D array. • printArray_2D () method to display 2D array. • belowAboveAvg () method which first finds the average of all random numbers entered in 1D array and then finds and displays the number of elements less than and greater than the average. swapLargestSmallest() method which swaps largest and smallest elements in the 1D array. sumRowsColumns () method which finds and displays sum of each row and each column of the…public int[] selectionSort(int[] array) {for (int i = 0; i < array.length - 1; i++) {int min = array[i];int minIndex = i;for (int j = i + 1; j < array.length; j++) {if (min > array[j]) {min = array[j];minIndex = j;}}if (minIndex == i) {array[minIndex] = array[i];array[i] = min;}}return array;}
- void showArray ( int a[ ], int size ); // shows the array in the format "int a [ ] = { 3, 7, 4, ... ,5, 6, 3} void showReverse ( int a[ ], int size ); // shows the array in reverse "int a [ ] = { 3, 6, 5, ... , 4, 7, 3 } " int lowest ( int a[ ], int size ); // finds and returns the lowest value in the array (should be 3) int highest ( int a[ ], int size ); // finds and returns the highest value in the array (should be 7) int sumArray ( int a[ ], int size ); // calculates and returns the sum of all values in the array float averageVal ( int a[ ], int size ); // calculates and returns the average of all values in the array int count5 ( int a[ ], int size ); // returns how many times the number 5 appears in the array int firstMinusLast ( int a[ ], int size ); // returns the difference b/w the First and Last Array Element void showBeforeIndex( int a [ ], int index); // shows all array values before a specific index void done…JAVA ARRAY MANIPULATION QUESTION: make a method called manipulator that takes a double array as parameter and modifies it. The method will modify the array then print the array. The method must modify the existing array, it CAN NOT create a different array as the solution. The manipulator method will be a void method. Remember: To get an average of 2 digits you add them together then divide by 2. Average of x and y = (x+y)/2 Modifications the method will do: For every 2 consecutive elements in the array, both the elements are replaced by their average. If the number of elements in an array is odd don't modify the last number of the array. Basically, you find the average of 2 consecutive elements then replace both of the elements with that value. Examples: Array = {2.0,3.0} will be changed to {2.5,2.5} when passed to the manipulator method Array = {2.0,3.0,45} will be changed to {2.5,2.5,45} when passed to the manipulator method Array = {2.0,3.0,45,55} will be changed to…Code Big Oh Notation my array = array(ï,[1,2,3,4,5|) for i in my_array print(i) 1. Code Big Oh Notation _print("Step 2") print(my_array[3]) 2. Code Big Oh Notation 3. print("Step 3") my_array.append(6) print(my array)
- 8. Repetition Use Python Language Write a method that takes in an array as a parameter and counts the repetition of each element. That is, if an element has appeared in the array more than once, then its 'repetition' is its number of occurrences. The method returns true if there are at least two elements with the same number of 'repetition'. Otherwise, return false. Input: {4,5,6,6,4,3,6,4} Output: True Explanation: Two numbers repeat in this array: 4 and 6. 4 has a repetition of 3, 6 has a repetition of 3. Since two numbers have the same repetition output is True. Input: {3,4,6,3,4,7,4,6,8,6,6} Output: False Explanation: Three numbers repeat in this array:3,4 and 6 .3 has a repetition of 2, 4 has a repetition of 3, 6 has a repetition of 4. Since no two numbers have the same repetition output is False.void shiftLeft(int array[], int size, int& numUsed, int index) { index = array[0]; for(int i = 1; i <= size - 1; i++) { array[i - 1] = array[i]; } array[size-1] = index; } void shiftRight(int array[], int size, int& numUsed, int index) { index = array[numUsed-1]; for(int i = numUsed - 2; i >= 0; i--) { array[i + 1] = array[i]; } array[0] = index; } how do i fix my shift right function.Design and implement a method to double all elements of an array. Important: You don’t need to test test method in main(). You don’t need to initialize the array. pubilc static void doubleElements(int [] arr) { }
- Method Details: public static void rotate(int[] array, boolean leftRotation, int positions) Rotates the provided array left if leftRotation is true; right otherwise. The number of positions to rotate is determined by positions. For example, rotating the array 10, 20, 7, 8 two positions to the left will update the array to 7, 8, 10, 20. Only arrays with 2 or more elements will be rotated. Hint: adding private methods that rotate an array one position to the left and one position to the right can help. Parameters: array - leftRotation - positions - Throws:java.lang.IllegalArgumentException - When a null array parameter is providedAssume that the following program segment is executed. What is the last element of testArray2 after the execution of the statement sortArray1(testArray2);? *84. Refer to the following method that finds the largest value in an array. /** Precondition: arr is initialized with int values. * @param arr the array to be processed * @return the largest value in arr */ public static int findMax(int[] arr) { int max = /* some value */; 0; int index %3D while (index max) arr[index]; max = index++; return max; } Which replacement(s) for /* some value */ will always result in correct execution of the findMax method? Integer. MIN _VALUE III. I. II. Integer.MAX_VALUE arr[0]
