Prove that the general solution of the differential equation √√1+cos(t) d0=(√1 + cos(t) — t sin(t) 0(t))dt is - -2t√√1+cos(t)+4√√1-cos(t) Se dt + C 0(t) = C 2t√√11 cos(t) 4√1 cos(t)
Prove that the general solution of the differential equation √√1+cos(t) d0=(√1 + cos(t) — t sin(t) 0(t))dt is - -2t√√1+cos(t)+4√√1-cos(t) Se dt + C 0(t) = C 2t√√11 cos(t) 4√1 cos(t)
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 34CR
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