Propose an appropriate base to carry out the transformation below and use it as part of a curly arrow mechanism for the whole process. Meo ༠ OMe 1. base 2. ' ', Meo OMe
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Solved in 3 steps with 1 images
- 2. Show the step-by-step process. Do not use shortcut methods. Make it as detailed as it can be. ENCODE (not hand-written)!3. Show the steps necessary to transform the acid on the left into the compound on the right. Be sure to use SOCI₂. a) CH,OCH,CH,COH b) CH,OCH₂CH,COH CH,OCH₂CH₂COCH₂CH₂C CH₂OCH₂CH₂CN(CHCan someone help me explain which sequence goes from most to least basic? The CH4 is throwing me off.
- ew topic [References Draw both resonance structures of the anion formed by the reaction of the most acidic C-H bond of the compound below with base. H3C SCH3 • Include all valence lone pairs in your answer. • For structures having different hydrogens of comparable acidity, assume that the reaction occurs at the less- substituted carbon. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate resonance structures using the → symbol from the drop-down menu. C P opy aste 11:58 M 18 52% 4/11/2021Please offer an easy and concise explanation for part a only! I understand part b alreadyDraw compound B (do not include lone pairs in your drawings but drawings must include counter ions). Edit XYour answer is incorrect. Try again. Draw compound C. Edit X Your answer is incorrect. Try again. Draw compound D.
- Draw out neatlyyyy1. C is basic and is also known as sulfonamide group. * TRUE FALSE 2. A is a an amide and imparts water solubility to the molecule. * TRUE FALSE 3. D is an example of a heterocyclic aromatic ring. * TRUE FALSE 4. B is a little more hydrophilic than D. This is because B does not contain a heteroatom in its ring. * TRUE FALSE 5. B is an aromatic ring and imparts lipid solubility to the molecule. * TRUE FALSE3. Show the steps necessary to transform the acid on the left into the compound on the right. Be sure to use SOC1,. a) (CH3)»CCH;COH (CH3),CCH2CNHCH;CH=CH2 b) (CH3);CCH2COH (CH3);CCH2COCH,CH3