procedure gcd(a,b: positive integers) x := a y := b while y # 0 begin r := x mod y x := y y :=r end { gcd(a,b) is x when y = r = 0} (Try example gcd(9, 6))
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Try to compute gcd or lcm ( gcd(9, 6) or lcm(9,6) ) by the following
Step by step
Solved in 4 steps with 1 images
- Ex: Let A1 ={x, y}, A2 ={1, 2}, and A3 ={a, b}, Find A1 × A2, (A1 × A2) × A3, A1 × A2 × A3.sum = 0; for (int i = 1; i< n; i = sum++ || 2*i)2. code locations Consider the following C code and the corresponding assembly code: void baz(int a, int * p) { pushq %rbp movq %rsp,%rbp subq $16,%rsp int c; C = a-*p; movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax),%eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 if (c) { int d = c*2; movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) *p -= d; movl 24(%rbp),%rax movl (%rax),%eax subl -8(%rbp),%eax movl %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: (continued on next page)
- le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"A = {1,2,3} B = {1,2,3} C = {5,6,7} D = {0,1,2,3,4,5} Is A = C?Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?
- Given the following pseudocode: function fun2(n) { var outer_count = 0; var inner_count %3D for (i=0; i 0, as an expression of normal arithmetic and n, what is the value of outer_count that counts the number of times the outer loop executes? Enter an expression Fun.2.inner: Assuming n E N and n > 0, as an expression of normal arithmetic and n, what is the value of inner_count that counts the number of times the inner loop executes? Enter an expressionConsider the following function: public void bSearch(int[] A, int value, int start, int end) { if (end value) { return bSearch(A, value, start, mid); } else if (value > A[mid]) { return bSearch(A, value, mid+1, end); } else { return mid; } } The mutation program P' changes the part as shown below. } else if (value > A[mid]) { return bSearch(A, value, mid+2, end); } else { return mid; } A test input is given t1: {A = [2, 3, 5, 7, 10, 11], value = 6, start=0, end=5}. Which statement below best describes the mutant with regards to the test input? O a. t1 resolves mutant P O b. The mutant P' with regards to test input t1 is live.void deleteRange( int from, int to) { int i, j = 0; for (i = 0; i < counter; i++) { if (i <= from - 1 || i >= to + 1) { A[j] = A[i]; j++; } } for (int i = 0; i < j; i++) cout << A[i] << " "; } Above method deletes range of elements from an array. Please explain the logic of above code in simple english (algorithm and comments).