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- At 0-, no currrent flows through the capacitors because they are open, how did you combine the capacitors for the voltage divider since it is the capacitance value and not reactance, is it right? Can we just combine the capacitance value? Please explain. I did not understand..1. What impedance vector 0 – j22 represents:A. A pure resistance.B. A pure inductance.C. A pure capacitance.D. An inductance combined with a resistance.A capacitor has a reactance of 40 when operated on a 50 Hz supply. Determine the value of its capacitance. In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltage
- What impedance vector (0- j15) Ohms represents:A. A pure resistance. C. A pure capacitance.B. A pure inductance. D. An inductance combined with a capacitance.Support that there. Icincuit Esithu an reasistanee on the and capacitance of /4 F. The EMF is ) 4 Cos 2t , The initial is an RC Cnerat current. The alternating cincuit is '/ 2 L Elt) the cincuit is qu(0) = 1V. Find the charge on the cincuit after t seconds. charge onA 20-ohm resistor and a capacitor are connected in series with a battery of 60 volts. At t = 0, there is no charge on the capacitor. Find the capacitance if the current at t = 5 seconds is 3/e^s amperes. Ans. 0.05 Farads
- a) The voltage across a 20uF capacitance is v. = 50 sin( at - 80) volts and Frequency equal to 100 Hz. Determine the current through the capacitor i and sketch its waveform. b) Define phasorRequired information Problem 06.037 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS The current through a 17-mH inductor is 4 sin 100t A. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Problem 06.037.a - Voltage across an inductor Find the voltage vt). The voltage is cos 100t V.An Inductor has an internal resistance of 10 Ohms and an inductance of 0.5H. What is it's impedance to a 60 Hz supply? O A. 10 Ohms B. 10.50 Ohms OC. 10.01 Ohms D. 188.77 Ohms O E. 180 Ohms
- 2_53528980697... -> For the circuit shown below, detemine the voltage of the -j10 2 capacitive reactance. -j5 0 ILOA(T) ==j102 jlon is Q 102 O 0.5L-90 52 A.A capacitor C is connected in series with a 400 resistor across a supply of frequency 60 Hz. A current of 3 A flows and the circuit impedance is 500. Calculate: (a) the value of capacitance, C, (b) the supply voltage, (c) the phase angle between the supply voltage and current, (d) the p.d. across the resistor, and (e) the p.d. across the capacitor. Draw the Phasor diagram.For the given waveforms, waveform C * the waveform D and E. Degrees 30 60 90 180 210 360 540 M A pure inductor has a reactance value of 425 2. If this inductor is supplied with a frequency of 60 Hz and current changing at the rate of 10 A/s, find the induced e.m.f. Induced e.m.f. =