Problem # 6.0 For the tension member shown, compute the tensile design strength. Weld -6" PL 4X6 A36 steel
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- Considering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.WT12 x 38 Longitudinal welds Given: Properties of WT12 x 38: A, = 11.2 in? y = 3.0 in. b = 8.99in. Use A992 Steel: F, = 50 ksi F = 65 ksi LL = 3 DL %3D %3D tw = centroidal distance bf A. Governing Ultimate Tensile Capacity based on Yielding of gross section Round your answer to 0 decimal places.Topic:Welded Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A tension member consists of a double angle section with long legs back to back. The angles are attached to a 9.5 mm thick gusset plate. Fu = 400 MPa Fy = 248 MPa for angular section. Fw = 480 MPa for 8 mm fillet weld. Reduction factor U = 0.80 Prop. of One Angle L 125m x 75m x 12.7 m A= 2419 mm2 y=44.45 mm Questions: a) Compute the design strength capacity of one angle. b) Compute the base metal shear strength (gusset plate) per unit length. c) Compute the length L1 and L2.
- Determine the tensile strength of the welded A992 WT4×20. WT4× 20 PL – Transverse weldTopic:Bolted Steel Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A 12.5 mm x150 mm plate is connected to a gusset plate having a thickness of 9.5 mm.Diameter of bolt = 20 mm Both the tension member and the gusset plate are of A 36 steel. Fy = 248 MPa, FU = 400 MPa. Shear stress of bolt Fnv = 300MPa. Questions: a.Determine the shear strength of the connection. b.Determine the bearing strength of the connection. c. Determine the block shear strength of the connection.Centroid + Inertia 200 x 20 mm Plate The strength of the rolled section shown is increased by combining S section, channel, plate and then welded. 1. Determine the location of its centroid; and 5310 x 47.3 C310 x 30.8 2. Determine the moments of inertia of the composite section with respect to its centroidal x and y Semi-circle Weld, 10mm radius axes.
- Topic:Welded Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A 150 mm x 90 mm x 12 mm angular section is welded to a gusset plate as shown. Area of the angle is 2736 sq.mm, allowable shear Fv is 150MPa, Allowable tensile stress Ft = 0.6Fy with Fy = 250 MPa. Questions: a) Design force P b) Total required length of weld using 12 mm fillet weld c) Value of “b”Determine the design tensile strength of plate (200x8 mm) connected to 10-mm thick gusset using 20 mm bolts as shown in the figure, if the yield and the ultimate stress of the steel used are 250 MPa and 410 MPa, respectively. Add 1mm around the bolt for the hole. Use LRFD method. Plate 8-mm thick 2 3 40+ 30 301 T 200 mm Gusset 10-mm thick 3af 30 2_3 *40 40+ 50,54 +40The welded girder shown in the accompanying illustration has an external shear V₁ = 300 k and V₁ = 350 kat a particular - section. Determine the fillet weld size required to fasten the plates to the web if the SMAW process is used. E70. Use LRFD and ASD. PL1 x 16 I Web x 48 PL1 x 16
- The diagonal at the left to the connection is a double angle 90 mm x 90 mm x 8 mm, with area of 2700 mm?, bolted to the 8 mm thick gusset plate. Bolt diameter = 16 mm Bolt hole diameter = 18 mm Bolt bearing capacity, Fp = 480 MPa Bolt shear strength, Fv = 68 MPa Steel plate strength and stresses are as follows: Yield strength, Fy 248 MPa Ultimate strength, Fu = 400 MPa Allowable tensile stress on the gross area = 0.60 Fy Allowable tensile stress on the net area = %3D 0.50 Fu Allowable shear stress on the net area = 0.30 Fu Bolt bearing capacity, Fp = 1.2 Fy Calculate the allowable tensile load, P(kN) under the following conditions: %3D* A 76 mm x 76mm x 6mm angular section is welded to a gusset plate having a thickness of 8mm as shown in the figure. The length L1 equals 125mm and L2 is 65mm. The angular section has a cross sectional area of 929mm2, Fy=248 MPa, Fu=400MPa. Determine the value of tensile force P based on block shear in gusset plate along the weld in kN. Allowable stresses: Allowable tensile stress (gross area) = 0.6Fy Allowable tensile stress (net area) = 0.50Fu Allowable shear stress (net area) = 0.30Fu P gusset plate L₂= 65 mm 25 mmFor the tension member shown, compute the following. a. The tensile design strength. b. The allowable tensile strength. Weld PL 14 x 6 A36 steel