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- Subject: Engineering Economics Lesson: Capitalized Cost The first cost of a certain piece of equipment is P 50,000. It will have an annual operating cost of P 20,000 and P 5,000 salvage value after its 5 year life. At an interest rate of 10% per year, what is the capitalized cost of the equipment? (Show solution)A piece of asset was purchased 4 years ago. Current market value is now $13,000. Estimated Future Market Values and AOC's: (Assume the interest rate is 10% per year) are as follows. Market EOY value, $ AOC 1 9000 2500 8000 2700 6000 3000 4 2000 3500 4500 What is the ESL? 2 years 3 years 4 years 45yearsHomework:Homework 1 Question 5, Problem 4-12 (algorithmic) HW Score: 0%, 0 of 6 points Points: 0 of 1 Save Question content area top Part 1 A new oven will save $130 per year in electricity expense. How much can we afford to pay for this oven if it is expected to last 13 years? The interest rate is 13% per year. The affordable amount of payment is $ ?
- Initial Cost: ($300,000)The Study Period: 15 yearsSalvage (Market) Value of the Project: 12% of the initial costOperating Costs in the first year: ($7,500)Operating Costs increase by 5% per yearBenefits in the first year: $30,000 Benefit increase by 13% per yearMARR: 9% per year 1)Determine the NPW, AW, FW of the project. 2) Is the Project acceptable? WHY?Two lathes are being considered in the manufacture of certain machine parts. Data is given below, all cost in peso: LATHE A LATHE B First Cost 40,000 56,000 Salvage Value 5,000 7,000 Annual Maintenance 2,000 2,800 Operation, Cost/hour 4 3.5 Life, in years 10 12 Time per part (hours) 0.40 0.25 REQUIRED: Determine the number of machine parts/year that could be produced so that 2 lathes will be equally economical if the MARR is 18%. Use AWM If the number of parts is 10,000 units, which lathe will you recommend? Use ROR If the number of parts is 10,000 units, which lathe will you recommend? Use PWM If the number of parts is 10,000 units, which lathe will you recommend? Use EUACCell (A) stands for the total cost of 9 units. Its value should be ____. a) 151.65b) 323.52c) 909.80d) 252.75
- Which alternative in the table below should be selected when the MRR = 6% per year? The life of each Kalternative is 10 years. Increment Considered A Investment cost A (Annual Revenues less. Costs) IRR on A Investment Cost A(A-DN) $800 $154 14.1% The IRR on A(C-B) is %. (Round to one decimal place.) A(B-A) $700 $114 10.0% A(C-B) $1,100 $170 ? A(D-C) $1,300 $130 2Least-cost abatement curve Solar PV Nuclear Feasible set Coal CCS new build Low-penetration wind Coal CCS retrofit High-penetration wind Iron and steel CCS new build 8.37 billion euros Cost of abatement (billions € = cost per tonne abated x gigatonnes abated) %3D Environmental quality, E (amount abated, GTCO,) 11.2 GTCO, 4.94 GTCO,You invested $100,000 in a project and received $40,000 at n = 1, $40,000 atn = 2, and $30,000 at n = 3 years. You need to terminate the project at the end of year 3. Your interest rate is 10%; what is the project balance at the time of termination?(a) Gain of $10,000(b) Loss of $8,039(c) Loss of $10,700(d) Just break even
- Lifewear, a manufacturer of women's sports clothes, is considering adding a line of skirts and jackets. The production would take place in a part of its factory that is currently not being used. The first output would be available in time for the 2021 fall season. The following information is available. Answer parts (a) through (d). New Product Line Information First cost in 2020 ($) 15,100,000 Planned output (units/year) 324,000 Observed, current dollar MARR before tax Study period Materials 0.25 6 years Year 2020 Prices ($/unit) Labour 12 8.25 35 Output a. What is the real internal rate of return? (This is most easily done with a spreadsheet.) The real internal rate of return is about percent. (Round to one decimal place as needed.) b. What inflation rate will make the real MARR equal to the real internal rate of return? The inflation rate would need to be about percent. (Round to two decimal places as needed.) c. Calculate the present worth of the project under three possible future…A firm has two alternatives for the improvement of its current production system. The data are as follows: Мachine A Мachine B First Cost – P7,397,822 First cost – P7M Annual operating cost – P283,742 Service life – 4 years Salvage value - P171,201 Using the Annual Equivalent Cost (AEC) Method and with the firm's interest rate of 21% cpd. annually, what the AEC of Machine A? Annual operating cost – P300T Service life – 6 years Salvage value - P200T3. Evaluate the two machines below, using ROR analysis. Which machine should be selected, if MARR is 10%? Remember, the ROR equation should be set up to ensure equal service. Mach B -15,000 -25,000 -400 6,000 Mach A First cost ($) AOC ($) Salvage value (4) Life (yrs) -1,600 3,000 6