Problem 12-11 The acceleration of a particle as it moves along a straight line is given by a = bt + c. If s = s, and v = v, whent = 0, determine the particle's velocity and position when t= t1. Also, %3D determine the total distance the particle travels during this time period. m c = -1 2 S m Given: b = 2 so = 1 m vo 2 = 6 s 3 S S

Problem 12-11 The acceleration of a particle as it moves along a straight line is given by a = bt + c. If s = s, and v = v, whent = 0, determine the particle's velocity and position when t= t1. Also, %3D determine the total distance the particle travels during this time period. m c = -1 2 S m Given: b = 2 so = 1 m vo 2 = 6 s 3 S S

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A projectile exits a launch tube with a velocity of 255 m/s. While accelerating through the launch tube, the projectile moves a distance of 1.850 m. Determine the acceleration of the projectile (assume a uniform acceleration). Which equation should you use to solve for acceleration? a. Ax = 1/2(v, + v)At b. Ax = v,At +(1/2)aAt? c. v? = v,? + 2aAx d. Vf = v, + aat
Physics 30S Science & Technology 2240 Grant Ave. Winnipeg. MB R2C IL6 Shaflesbury High School Motion: Speed/Velocity & Acceleration Ad V = At a = Average Velocity, 1. A man jogs 5.0 km (5000 m) in 27 minutes. a) What is the time interval (At) in seconds? b) Calculate his average speed in metres per second (m/s). Average Acceleration, At 2. An object has a position of 13 metres west. 5.0 seconds later it's at 7 metres east. a) What was the initial position? b) What was the change of position or displacement (Ad)? c) What was the average velocity? 3. A world class sprinter runs 100.0 m in 8.90 s. What was his average speed? 4. A hiker gets lost in a forest. He walks half-way around a circle with a radius of 2.1 km in 2.0 hours. a) What distance did he walk? b) What was his average speed? c) What was his displacement? d) What was his average velocity? WE S C-2rr 5. A car has an average highway speed of 90 km/h or 25 m/s. At this speed; how long will it take to drive to Kenora which is 190…
1. The motion of a particle along the x-axis is described by the equation v= (3m/s2)t + (0.5m/s3)t2 where x is in meters, and t is in seconds. Position of the particle 3 seconds after starting = 6m Displacement from 2 sec to 5 sec = 3m Average velocity during first 5 seconds = 1m/s Determine the following: d. Velocity at t= 4secse. Average acceleration during the second 3 secondsf. Acceleration at t = 5 secs
94 in x 114 in (24 cm x 29 cm) with Prongs EAR -rocket Portfolio Stenes, inc Distributed 3. A ball is thrown straight up with an initial velocity of 128 ft/sec., so that its height 844106 031076 (in feet) after t seconds is given by s(1) = -16t2 +128 A. What is the average velocity of the ball over the time intervals? a. [2, 3] b. [2, 2.5] c. [2. 2.1] B. What is the instantaneous velocity at time t 2? C. What is the instantaneous velocity at time t-5? Is the ball rising or falling? D. When will the ball hit the ground? An object is dropped from a certain height. It is known that it will fall a distance s, in
Problem 1 A cannon ball on the ground is fired at 35 with an initial velocity of 250 m/s. a. How long will it take to hit the ground? b. How far from the cannon ball will it hit the ground? c. Compute for maximum height to be reached by the cannon ball. Given: V. - 250 m/s 35 g- 9.8" Solution: a. The time of flight of the cannon ball 2v, sin 500m/s(sin 35°) 500m/s(0.57) _ 28Sm/s = 29.08s 9.8m/x 9.8m/s 9.8m/s b. The range of the cannon ball v, sin 0 (250m/s) 2 sin 35° 62500m2/s 2(0.57) 9.8m/s R 9.8m/ s 62.500m /s(0.9397) 58,730.79m /s? 9.8m/s 5,992.94m 9.8m/s c. The maximum height that the cannon ball reached v sin 0 (250m/s)²(sin 35")(sin35") 62.500m /s²(0.57) 2(9.8m/s) Утах 28 19.6m/s 62,500m² /s²(0.32899 20,561.87m /s- 1,049.08m 19.6m/s 19.6m/s This time, it's your turn to solve the next problem. Problem 2 An arrow is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal. 10 a. How long will it take to hit the ground? b. How far from the…
7. The motion of the particle is given by a = 10t – t2 , a is in m/s² and t is in sec. How far will it move %3D - before starting to reverse its motion. Draw the a-t, v-t and s-t curve up to this time. Ans. 1406.25 m.
4. The acceleration of a particle is given by a = Avt where A = 2.0 m/s5/2. At t = 0, v = 7.5 m/s and x = 0. What is the displacement at t = 5.0 s? a =AVt %3D On nhiect has velocity Yo (t) = 31+1î 31+1i m/s at time t = 0.00 s. The acceleration of the
A rabbit runs across a parking lot on which a set of coordinate axis has been drawn. The coordinates of the rabbit’s position as a function of time t are given by: x = -0.3t2 + 5t + 28 and y = 0.22t2 - 8t + 30 with t in seconds and x and y in meters. What is the velocity at t= 10 sec? A. 0.6 i + 0.4 j B. -0.2i +1.6j +30 C. -i - 3.6 j D. 4i + 2j
2. The rocket starts from rest to and travels straight up. Its . C. height above the ground can be approsimated by the functions S = bt+ct*where "b" and "e are constants. At t-10 seconds, the rockets velocity and acceleration are v229 m/s and an28.2 m/s. a Determine the value of S at t-5 seconds b. Determine the value of its velocity at t-5 seconds Determine the value of its acceleration at t-5 seconds
3. Shown below is the acceleration function for a particle over the approximately first two seconds of its motion. Draw an approximate graph of velocity as a function of time assuming v, = 0 m/s. alt) t 20 15 10 5. 0.5 1.0 1.5 2.0 2.5 4. Let vector A point from the origin into the first quadrant of the xy plane and vector B point from the origin into the third quadrant. The vector Ă – B must be in which quadrant?
2. A cheetah moving in a constant acceleration covers the distance between two points 70.0m apart in 7.00s. Its speed as it passes the second point is 15.0m/s a. What is its speed at the first point? b. What is its acceleration?
3. Train A travels with a constant speed Va=120kph along the straight andlevel track. The driver of a car B. anticipating the railway gradecrossing C decreases the car speed of 90kph at the rate of 3m/s2a. Determine the velocity of the train relative to the carb. Determine the acceleration of the train relative to the car