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Predict the major product formed by 1,4-addition of HCl to cyclopentadiene
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- Bicyclo-2,5-heptadiene can be prepared in two steps from cyclopentadiene and vinyl chloride. Provide a mechanism for each step.Identify two alkenes that react with HBr to form 1-bromo-1-methylcyclohexane without undergoing a carbocation rearrangement.Steps for Converting 3-bromocyclohexene to 3methenecyclohexene
- 7. Reaction product of 3-methyl-butene with hydrochloric acid:a) 2-methyl-3-chlorobutaneb) 3-methyl-3-chlorobutanec) 2-chloro-3-methyl butaned) 2-chloro-2-methyl butane 8. What type of reaction takes place when CO2 + H2O and energy are obtained from 3-methyl butyne?a) Hydrogenationb) Halogenationc) Partial oxidationd) Total oxidationUsing Markovnikov's rule, predict the position of the Cl atom in the major product from the reaction of 1-methylcyclohexene with HCI. II II IV O II(dehydrobromination) A chemist carried out an elimination reaction of 1,1-dimethyl-2- bromocyclopentane. The chemist expected the reaction to yield alkene Z as product. However, alkene Z DID NOT form. Instead, three alkenes were produced: one alkene was the major product, the other two alkenes was the minor products. What was the major alkene product that formed? Br Select one: A. I B. II C. IV D. III alcohol HEAT || Z = + (HBr) IV
- What alkene should be used to synthesize 3-bromohexane? 3-bromohexaneWhich isomer of 1-bromo-3-isopropylcyclohexane reacts faster when refluxed with potassium tert-butoxide, the cis isomer or the trans isomer? Draw the structure of the expected product from the faster-reacting compound.Name the alkene below. Use ONLY E/Z designators to indicate stereochemistry. H CH3 H3C C=C H2C=CHCHÇH H ČH3
- Addition of HBr to 1,3-Butadiene produce A- 3-Bromo-1-butene B- 1-Bromo-2-butene C- 3,4-dibromo-1-butene D-A and B A O BO C OWhich alkene when hydrochlorinated (hydrohalogenation reaction) will give this alkyl halide as product H3C CH3 CI CH3 2-methyl-1-pentene 2,3-dimethyl-1-pentene 2-methyl-2-butene 3-methyl-2-penteneAddition of HBr to allene (CH2 = C = CH2) forms 2-bromoprop-1-ene rather than 3-bromoprop-1-ene, even though 3-bromoprop-1-ene is formed from an allylic carbocation. Considering the arrangement of orbitals in the allene reactant, explain this result.