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Part B Calculate the nonequilibrium concentration of ethanol in yeast cells, if AG = -38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above. Express your answer with the appropriate units. μA Concentration = Value Submit Request Answer Units ?

Part B Calculate the nonequilibrium concentration of ethanol in yeast cells, if AG = -38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above. Express your answer with the appropriate units. μA Concentration = Value Submit Request Answer Units ?

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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solve part b

Part B Calculate the nonequilibrium concentration of ethanol in yeast cells, if AG = −38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above. Express your answer with the appropriate units. HÅ Concentration = Value Submit Request Answer Units ?
Transcribed Image Text:Part B Calculate the nonequilibrium concentration of ethanol in yeast cells, if AG = −38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above. Express your answer with the appropriate units. HÅ Concentration = Value Submit Request Answer Units ?
For part B of this problem, use the following standard reduction potentials, free energies, and nonequilibrium concentrations of reactants and products: ADP 220 μΜ ATP = 3.10 mM glucose = 5.10 mM NAD+ = 350 μM P₁ = 5.90 mM pyruvate = 62.0 µM NADH = 15.0 μM Part A >0 half reaction <0 Submit - CO₂: = 15.0 torr NAD+ + H+ + 2e¯ 2pyruvate + 6H+ + 4e¯ Consider the last two steps in the alcoholic fermentation of glucose by brewer's yeast: pyruvate + NADH + 2H+ Do you predict that ASO for this reaction is > 0 or < 0? Previous Answers → NADH →glucose → ethanol + NAD+ + CO₂ ATP + H₂O → ADP + P; +H+ E° (V) -0.315 -0.590 AGO = -64.4 kJ/mol AGO = -32.2 kJ/mol pyruvate + NADH+ 2H+ → ethanol + NAD+ + CO₂ Correct As written 4 reactants combine to produce 3 products (there are 2 mol H+ as written, thus there are 4 reactants). Typically, producing fewer products than reactants would require a loss of entropy; however, in this case one of the products is a gas (and none of the reactants are gases). Gas formation is typically associated with a significant increase in entropy. Thus, the prediction that the entropy change is > 0 is reasonable.
Transcribed Image Text:For part B of this problem, use the following standard reduction potentials, free energies, and nonequilibrium concentrations of reactants and products: ADP 220 μΜ ATP = 3.10 mM glucose = 5.10 mM NAD+ = 350 μM P₁ = 5.90 mM pyruvate = 62.0 µM NADH = 15.0 μM Part A >0 half reaction <0 Submit - CO₂: = 15.0 torr NAD+ + H+ + 2e¯ 2pyruvate + 6H+ + 4e¯ Consider the last two steps in the alcoholic fermentation of glucose by brewer's yeast: pyruvate + NADH + 2H+ Do you predict that ASO for this reaction is > 0 or < 0? Previous Answers → NADH →glucose → ethanol + NAD+ + CO₂ ATP + H₂O → ADP + P; +H+ E° (V) -0.315 -0.590 AGO = -64.4 kJ/mol AGO = -32.2 kJ/mol pyruvate + NADH+ 2H+ → ethanol + NAD+ + CO₂ Correct As written 4 reactants combine to produce 3 products (there are 2 mol H+ as written, thus there are 4 reactants). Typically, producing fewer products than reactants would require a loss of entropy; however, in this case one of the products is a gas (and none of the reactants are gases). Gas formation is typically associated with a significant increase in entropy. Thus, the prediction that the entropy change is > 0 is reasonable.
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