Part A: The Fixed Point Problem is: Given a sorted array of distinct elements A[1...n), determine whether there exists some i such that A[i] = i. Consider the following recursive algorithm (and assume that the function returns nothing if the array A is empty): function f(A[1...n]): m = []; if A[m] = m return m; if A[m] > m return f(A[1...m-1]); if A[m] m so the algorithm always misses half the list. O Yes. If A[m]>m, then it is impossible to have A[i] = i for any i 2 m (and the same for the other case). O No. It is impossible for A[m]

Part A: The Fixed Point Problem is: Given a sorted array of distinct elements A[1...n), determine whether there exists some i such that A[i] = i. Consider the following recursive algorithm (and assume that the function returns nothing if the array A is empty): function f(A[1...n]): m = []; if A[m] = m return m; if A[m] > m return f(A[1...m-1]); if A[m] m so the algorithm always misses half the list. O Yes. If A[m]>m, then it is impossible to have A[i] = i for any i 2 m (and the same for the other case). O No. It is impossible for A[m]

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 7SA

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For funX |C Solved xb Answer x+ CodeW X https://codeworko... 田) CodeWorkout X267: Recursion Programming Exercise: Cumulative Sum For function sumtok, write the missing recursive call. This function returns the sum of the values from1 to k. Examples: sumtok(5) -> 15 Your Answer: 1 public int sumtok(int k) { 2. } (0 => ) return 0; 3. } else { return > 6. { Check my answer! Reset Next exercise 1:09 AM
Lecture: Analysis of Algorithms >> Recursion: Tail and Non-Tail << Write a function to find the largest element of an array using;a.Tail recursionb. Non-tail recursion
: In searching an element in an array, linear search can be used, even though simple to implement, but not efficient, with only O(n) time complexity. Assuming the array is already in sorted order, modify the search function below, using a better algorithm, so the average time complexity for the search function is O(log n). include <iostream> using namespace std; int search(int al), int s, int v) { 1/ Modify below codes. for (int i = 0; i <s; i++) { if (a[i] = v) return i; return -1; int main() { int intArray:10] = { 5, 7, 8, 9, 10, 12, 13, 15, 20, 34); // Search for element '12' in 10-elements integer array. cout << search(intArray, 10, 12); // '5' will be printed out. // Search for element '35' in 10-elements integer array. cout << search(intArray, 10, 35); // '-1' will be printed out. // Index '-l' means that the element is not found. return 0;
Your main task is to write a recursive function sierpinski() that plots a Sierpinski triangle of order n to standard drawing. Think recursively: sierpinski() should draw one filled equilateral triangle (pointed downwards) and then call itself recursively three times (with an appropriate stopping condition). It should draw 1 filled triangle for n = 1; 4 filled triangles for n = 2; and 13 filled triangles for n = 3; and so forth. Sierpinski.java When writing your program, exercise modular design by organizing it into four functions, as specified in the following API: public class Sierpinski { // Height of an equilateral triangle with the specified side length. public static double height(double length) // Draws a filled equilateral triangle with the specified side length // whose bottom vertex is (x, y). public static void filledTriangle(double x, double y, double length) // Draws a Sierpinski triangle of order n, such that the largest filled //…
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