Part A A 15.6-kg mass fastened to the end of a steel wire with an unstretched length of 0.600 m is whirled in a vertical circle with angular velocity 2.10 rev/s at the bottom of the circle. The cross-sectional area of the wire is 1.20 x 10 2 cm?. Calculate the elongation of the wire when the mass is at the lowest point of the path. (Young's modulus of steel is 2.0 x 101 Pa) Express your answer in millimeters. Πνα ΑΣφ Al = mm Submit Request Answer

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A 15.6-kgkg mass fastened to the end of a steel wire with an unstretched length of 0.600 mm is whirled in a vertical circle with angular velocity 2.10 rev/srev/s at the bottom of the circle. The cross-sectional area of the wire is 1.20×10−2cm21.20×10−2cm2. 

Calculate the elongation of the wire when the mass is at the lowest point of the path. (Young's modulus of steel is 2.0×1011Pa2.0×1011Pa.) Express your answer in millimeters.
Problem 11.60
Part A
A 15.6-kg mass fastened to the end of a steel wire with an unstretched
length of 0.600 m is whirled in a vertical circle with angular velocity
2.10 rev/s at the bottom of the circle. The cross-sectional area of the
Calculate the elongation of the wire when the mass is at the lowest point of the path. (Young's modulus of steel is 2.0 x 1011 Pa.)
wire is 1.20 x 10 2 cm?.
Express your answer in millimeters.
?
Al =
mm
Submit
Request Answer
< Return to
Provide Feedback
Transcribed Image Text:Problem 11.60 Part A A 15.6-kg mass fastened to the end of a steel wire with an unstretched length of 0.600 m is whirled in a vertical circle with angular velocity 2.10 rev/s at the bottom of the circle. The cross-sectional area of the Calculate the elongation of the wire when the mass is at the lowest point of the path. (Young's modulus of steel is 2.0 x 1011 Pa.) wire is 1.20 x 10 2 cm?. Express your answer in millimeters. ? Al = mm Submit Request Answer < Return to Provide Feedback
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