Part 1 What is the probability that each indicated individual is a carrier of the disease allele? For people with no family history, assume that the probability of carrier status is f(Aa) I. 11. III. IV. Incorrect 1 1 O 0.0096 O 0.0192 Oo Ⓒ 0.25 O 0.125 2 2 A1 1 2 1/2 x 2/3 0.016 0.0768 0 1 (100%) 1/4 1/2 9... Part 2 What is the chance that Individual IV-I will get the disease? Incorrect Individual III-3 has a 100% chance of being a carrier. Individual III-4 has a chance of 0.0768, as calculated from the frequency in the population. Use this information to calculate the chance that the two carriers could have an affected offspring.

Part 1 What is the probability that each indicated individual is a carrier of the disease allele? For people with no family history, assume that the probability of carrier status is f(Aa) I. 11. III. IV. Incorrect 1 1 O 0.0096 O 0.0192 Oo Ⓒ 0.25 O 0.125 2 2 A1 1 2 1/2 x 2/3 0.016 0.0768 0 1 (100%) 1/4 1/2 9... Part 2 What is the chance that Individual IV-I will get the disease? Incorrect Individual III-3 has a 100% chance of being a carrier. Individual III-4 has a chance of 0.0768, as calculated from the frequency in the population. Use this information to calculate the chance that the two carriers could have an affected offspring.

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

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