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Page 81- Practice Problem 3.9 If the ride increases in speed so that T = 2.0S, what is arad? (this question can be answered by using proportional reasoning, without much arithmetic.) Answer: 49 m/s².

Page 81- Practice Problem 3.9 If the ride increases in speed so that T = 2.0S, what is arad? (this question can be answered by using proportional reasoning, without much arithmetic.) Answer: 49 m/s².

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Only practice problem 3.9 The second photo has background info to help solve the problem.
Page 76- Practice Problem 3.6 If the kicker gives the ball the same initial speed and angle but the ball is kicked from a point 25m from the goalpost, what is the height of the ball above the crossbar as it crosses over the goalpost? Answer: 1.2m. Page 77- Practice problem 3.7 Suppose the pear is released from a height of 6.00m above the archer's arrow, the arrow is shot at a speed of 30.0m/s, and the distance between the archer and the base of the tower is 15.0m. Find the time at which the arrow hits the pear, the distance the pear has fallen, and the height of the arrow above its release point. Answers: 0.54s, 1.4m, 4.6m. Page 80-Practice Problem 3.8 A more reasonable maximum acceleration for varying pavement conditions is 5.0m/s². Under these conditions, what is the maximum speed at which a car can negotiate a flat curve with radius 230m? Answer: 34m/s=76mi/h. Page 81- Practice Problem 3.9 If the ride increases in speed so that T = 2.0S, what is a rad? (this question can be answered by using proportional reasoning, without much arithmetic.) Answer: 49 m/s². Page 83 - Practice Problem 3.10 If the plane its airspeed of 240km/h, but the wind decreases, what is the wind speed if the plane's velocity with respect to earth is 15° east of north? Answer: 64 km/h. Page 84 - Practice Problem 3.11 If the pilot was forced to reduce the plane's speed to 150km/h, how much would she need to increase the angle at which the plane is pointing (relative to north) in order for the plane to continue to travel due north? Answer: 8.7°
Transcribed Image Text:Page 76- Practice Problem 3.6 If the kicker gives the ball the same initial speed and angle but the ball is kicked from a point 25m from the goalpost, what is the height of the ball above the crossbar as it crosses over the goalpost? Answer: 1.2m. Page 77- Practice problem 3.7 Suppose the pear is released from a height of 6.00m above the archer's arrow, the arrow is shot at a speed of 30.0m/s, and the distance between the archer and the base of the tower is 15.0m. Find the time at which the arrow hits the pear, the distance the pear has fallen, and the height of the arrow above its release point. Answers: 0.54s, 1.4m, 4.6m. Page 80-Practice Problem 3.8 A more reasonable maximum acceleration for varying pavement conditions is 5.0m/s². Under these conditions, what is the maximum speed at which a car can negotiate a flat curve with radius 230m? Answer: 34m/s=76mi/h. Page 81- Practice Problem 3.9 If the ride increases in speed so that T = 2.0S, what is a rad? (this question can be answered by using proportional reasoning, without much arithmetic.) Answer: 49 m/s². Page 83 - Practice Problem 3.10 If the plane its airspeed of 240km/h, but the wind decreases, what is the wind speed if the plane's velocity with respect to earth is 15° east of north? Answer: 64 km/h. Page 84 - Practice Problem 3.11 If the pilot was forced to reduce the plane's speed to 150km/h, how much would she need to increase the angle at which the plane is pointing (relative to north) in order for the plane to continue to travel due north? Answer: 8.7°
ed d EXAMPLE 3.9 A high-speed carnival ride In this example the motion is in a vertical circle. Passengers in a carnival ride travel in a circle with radius 5.0 m (Figure 3.24). The ride moves at a constant speed and makes one complete circle in a time T = 4.0 s. What is the acceleration of the passengers? SOLUTION SET UP Figure 3.25 shows our diagram. T=4.0 s a =? R=5.0 m A FIGURE 3.25 Our diagram for this problem. el sol obulinger sad nisi ob of 1997 sit Hi awodź ze at ga 2TR T V = Blux vis alloys adi The centripetal acceleration 1,² R arad = = 3.5 Relative Velocity in a Plane SOLVE We again use Equation 3.12: a = v²/R. To find the speed u, we use the fact that a passenger travels a distance equal to the circum- ference of the circle (27R) in the time T for one revolution: Q D 3.5 Relative Velocity in a Plane In Section 2.7, we introduced the concept of relative velocity for motion along a straight ◄FIGURE 3.24 Circular motion in a carnival ride. 2T (5.0 m) 4.0 s Video Tutor Solution is (7.9 m/s)² 5.0 m 83 = 7.9 m/s. = 12 m/s². REFLECT As in Example 3.8, the direction of a is toward the center of the circle. The magnitude of a is greater than g, the acceleration due to gravity, so this is not a ride for the faint-hearted. (But some roller coast- ers subject their passengers to accelerations as great as 4g.) Practice Problem: If the ride increases in speed so that T = 2.0 s, what is arad? (This question can be answered by using proportional rea- soning, without much arithmetic.) Answer: 49 m/s².
Transcribed Image Text:ed d EXAMPLE 3.9 A high-speed carnival ride In this example the motion is in a vertical circle. Passengers in a carnival ride travel in a circle with radius 5.0 m (Figure 3.24). The ride moves at a constant speed and makes one complete circle in a time T = 4.0 s. What is the acceleration of the passengers? SOLUTION SET UP Figure 3.25 shows our diagram. T=4.0 s a =? R=5.0 m A FIGURE 3.25 Our diagram for this problem. el sol obulinger sad nisi ob of 1997 sit Hi awodź ze at ga 2TR T V = Blux vis alloys adi The centripetal acceleration 1,² R arad = = 3.5 Relative Velocity in a Plane SOLVE We again use Equation 3.12: a = v²/R. To find the speed u, we use the fact that a passenger travels a distance equal to the circum- ference of the circle (27R) in the time T for one revolution: Q D 3.5 Relative Velocity in a Plane In Section 2.7, we introduced the concept of relative velocity for motion along a straight ◄FIGURE 3.24 Circular motion in a carnival ride. 2T (5.0 m) 4.0 s Video Tutor Solution is (7.9 m/s)² 5.0 m 83 = 7.9 m/s. = 12 m/s². REFLECT As in Example 3.8, the direction of a is toward the center of the circle. The magnitude of a is greater than g, the acceleration due to gravity, so this is not a ride for the faint-hearted. (But some roller coast- ers subject their passengers to accelerations as great as 4g.) Practice Problem: If the ride increases in speed so that T = 2.0 s, what is arad? (This question can be answered by using proportional rea- soning, without much arithmetic.) Answer: 49 m/s².
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