P 11.5-14 The source voltage in the circuit shown in Figure P 11.5-14 is Vs = 24 /30° V. Consequently, = 3.13 /25.4° A, I2 = 1.99 /52.9° A and V4 = 8.88 -10.6° V I Determine (a) the average power absorbed by Z4, (b) the average power absorbed by Z1, and (c) the complex power delivered by the voltage source. (All phasors are given using peak, not rms, values.) + V1 12 + V2 Z1 = 4 – j20 Z2 = 5 + j52 Vs Z3 = 3 + j82 Z4 4 13 +

P 11.5-14 The source voltage in the circuit shown in Figure P 11.5-14 is Vs = 24 /30° V. Consequently, = 3.13 /25.4° A, I2 = 1.99 /52.9° A and V4 = 8.88 -10.6° V I Determine (a) the average power absorbed by Z4, (b) the average power absorbed by Z1, and (c) the complex power delivered by the voltage source. (All phasors are given using peak, not rms, values.) + V1 12 + V2 Z1 = 4 – j20 Z2 = 5 + j52 Vs Z3 = 3 + j82 Z4 4 13 +

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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