Ozlg) + 4H*(ag) + 4e = 2H,0 +1.23 Br2(aq) + 2e = 2Br (aq) +1.07 NO, (ag) + 4H*(ag) + 3e = NO(g) + 2H,0 +0.96 Ag*(ag) +e = Ag(s) +0.80 Fe+(aq) +e Fe* (aq) +0.77 1,(6) + 2e = 21- (aq) +0.54 Ni(OH)2(9) + 20H (ag) Cu(s) NiO2(s) + 2H,0 + 2e = +0.49 Cu²+(ag) + 2e = +0.34 so- (ag) + 4H*(ag) + 2e = +0.17 AgBr(s) + e = Ag(s) + Br (aq) O°H+ (br)fosH +0.07 2H+(ag) + 2e = H,(g) Sn²+ (aq) + 2e Sn(s) -0.14 Ni+ (ag) + 2e = Ni(s) -0.25 Co*(ag) + 2e = Co(s) -0.28 PbSO,(6) + H*(ag) + 2e = Pb(s) + HSO, (ag) Cd2+(ag) + 2e = Cd(s) -0.36 -0.40 Fe*(ag) + 2e Fe(s) -0.44 Cr* (ag) + 3e = Cr(s) -0.74 Zn (ag) + 2e = Zn(s) 2H,О + 2г -0.76 H;(g) + 20H (ag) Al(s) -0.83 Al+ (ag) + 3e = -1.66 Mg*(aq) + 2e = Na*(ag) + e = Na(s) Ca+ (ag) + 2e K* (aq) +e Mg(s) -2.37 -2.71 = Ca(s) -2.76 K() -2.92 Li*(ag) +e Li(s) -3.05 *Sec Appendix Table C.9 for a more complete listing. 12 l'and Fe2*, Fe3+
Ozlg) + 4H*(ag) + 4e = 2H,0 +1.23 Br2(aq) + 2e = 2Br (aq) +1.07 NO, (ag) + 4H*(ag) + 3e = NO(g) + 2H,0 +0.96 Ag*(ag) +e = Ag(s) +0.80 Fe+(aq) +e Fe* (aq) +0.77 1,(6) + 2e = 21- (aq) +0.54 Ni(OH)2(9) + 20H (ag) Cu(s) NiO2(s) + 2H,0 + 2e = +0.49 Cu²+(ag) + 2e = +0.34 so- (ag) + 4H*(ag) + 2e = +0.17 AgBr(s) + e = Ag(s) + Br (aq) O°H+ (br)fosH +0.07 2H+(ag) + 2e = H,(g) Sn²+ (aq) + 2e Sn(s) -0.14 Ni+ (ag) + 2e = Ni(s) -0.25 Co*(ag) + 2e = Co(s) -0.28 PbSO,(6) + H*(ag) + 2e = Pb(s) + HSO, (ag) Cd2+(ag) + 2e = Cd(s) -0.36 -0.40 Fe*(ag) + 2e Fe(s) -0.44 Cr* (ag) + 3e = Cr(s) -0.74 Zn (ag) + 2e = Zn(s) 2H,О + 2г -0.76 H;(g) + 20H (ag) Al(s) -0.83 Al+ (ag) + 3e = -1.66 Mg*(aq) + 2e = Na*(ag) + e = Na(s) Ca+ (ag) + 2e K* (aq) +e Mg(s) -2.37 -2.71 = Ca(s) -2.76 K() -2.92 Li*(ag) +e Li(s) -3.05 *Sec Appendix Table C.9 for a more complete listing. 12 l'and Fe2*, Fe3+
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 150CP: Given the following two standard reduction potentials, solve for the standard reduction potential of...
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3
Transcribed Image Text:Ozlg) + 4H*(ag) + 4e =
2H,0
+1.23
Br2(aq) + 2e =
2Br (aq)
+1.07
NO, (ag) + 4H*(ag) + 3e = NO(g) + 2H,0
+0.96
Ag*(ag) +e = Ag(s)
+0.80
Fe+(aq) +e
Fe* (aq)
+0.77
1,(6) + 2e =
21- (aq)
+0.54
Ni(OH)2(9) + 20H (ag)
Cu(s)
NiO2(s) + 2H,0 + 2e =
+0.49
Cu²+(ag) + 2e =
+0.34
so- (ag) + 4H*(ag) + 2e =
+0.17
AgBr(s) + e =
Ag(s) + Br (aq)
O°H+ (br)fosH
+0.07
2H+(ag) + 2e =
H,(g)
Sn²+ (aq) + 2e
Sn(s)
-0.14
Ni+ (ag) + 2e =
Ni(s)
-0.25
Co*(ag) + 2e =
Co(s)
-0.28
PbSO,(6) + H*(ag) + 2e = Pb(s) + HSO, (ag)
Cd2+(ag) + 2e = Cd(s)
-0.36
-0.40
Fe*(ag) + 2e
Fe(s)
-0.44
Cr* (ag) + 3e =
Cr(s)
-0.74
Zn (ag) + 2e = Zn(s)
2H,О + 2г
-0.76
H;(g) + 20H (ag)
Al(s)
-0.83
Al+ (ag) + 3e =
-1.66
Mg*(aq) + 2e =
Na*(ag) + e = Na(s)
Ca+ (ag) + 2e
K* (aq) +e
Mg(s)
-2.37
-2.71
= Ca(s)
-2.76
K()
-2.92
Li*(ag) +e
Li(s)
-3.05
*Sec Appendix Table C.9 for a more complete listing.
12 l'and Fe2*, Fe3+
Transcribed Image Text:Based only on the half-reactions in table below, determine what spontaneous reaction will occur if the following substances are mixed
together. Include physical states in your answer.
Standard Reduction Potentials at 25 °Cc
Half-Reaction
E° (volts)
F2(g) + 2e
= 2F (ag)
+2.87
S,O,-(ag) + 2e =
2S0, (ag)
+2.01
PbO,(6) + HSO, (ag) + 3H*(ag) + 2e = Pbso,(6) + 2H,0
+1.69
2HOCI(aq) + 2H*(ag) + 2e
Mno, (ag) + 8H* (ag) + 5e =
Cl,(g) + 2H,0
+1.63
Mn²+(aq) + 4H,0
+1.51
Pb2+ (aq) + 2H,0
Br (ag) + 3H20
PbO2(s) + 4H+(ag) + 2e =
+1.46
BrO, (ag) + 6H*(aq) + 6e
Au*"(ag) + 3e
+1.44
Au(s)
+1.42
Cl(g) + 2
= 2CF (ag)
+1.36
O,lg) + 4H*(aq) + 4e =
2H,0
+1.23
Br2(aq) + 2e =
2Br (aq)
+1.07
NO, (aq) + 4H*(aq) + 3e = NO(g) + 2H20
Ag*(aq) + e
Fe+(ag) +e = Fe?+ (ag)
+0.96
Ag(s)
+0.80
||
+0.77
21 (ag)
NiO2(s) + 2H,0 + 2e =
Cu?+(ag) + 2e = Cu(s)
1,(s) + 2e
+0.54
Ni(OH)2() + 20H (aq)
+0.49
+0.34
so (aq) + 4H*(aq) + 2e =
AgBr(s) +e = Ag(s) + Br (ag)
H,SO,(ag) + H,0
+0.17
+0.07
2H*(aq) + 2e
H,(g)
Sn2+ (aq) + 2e = Sn(s)
-0.14
Ni?*(ag) + 2e
Ni(s)
-0.25
Co+(aq) + 2e
PbSO,(6) + H*(ag) + 2e = Pb(s) + HSO, (ag)
Cd2+(ag) + 2e = Cd(s)
Co(s)
-0.28
|
-0.36
-0.40
Fe*(ag) + 2e =
Fe(s)
-0.44
Cr* (ag) + 3e = Cr(s)
-0.74
Zn* (ag) + 2e = Zn(s)
-0.76
2H,0 + 2e = H,(g) + 20H(ag)
-0.83
Al+ (ag) + 3e = Al(s)
-1.66
Mg**(ag) + 2e =
Mg(s)
-2.37
Na*(ag) + e = Na(s)
-2.71
Ca+ (ag) + 2e = Ca(s)
-2.76
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