help with c++...pste indented code with the same output given plzz Output ExampleDefault Constructor: 0/1Single Parameter Constructor: 2/1Dual Parameter Constructor: 1/3Accessors / Mutators: 3/12GCD of the last fraction: 3GCD of 40 and 24: 8LCM of the last fraction: 12LCM of 3 and 5: 15Reducing the last fraction: 1/4 1. Implement a Rational Number class with the following specifications.Data membersa) numerator and denominatorFunctionsa) Constructors:1) default constructor2) single parameter constructor to create numerator/13) dual parameter constructor to create numerator/denominator4) Use constructor delegation across all constructors.b) Accessors and Mutators for both data members.c) Static recursive GCD function using Euclid's algorithm.d) Static LCM function for two numbers.e) Reduce function simplify a rational number. This function modifies its callingobject.f) Your program should work with the supplied driver program.NotesLCM (Least Common Multiple)This function returns the smallest multiple of a and b.Step 1: Multiply a and b to find a common multiple.Step 2: Divide the common multiple by the GCD of a and b.Step 3: Return the result of Step 2.Reduce:This function reduces a fraction to simplest terms (i.e. 9/12 to 3/4).Step 1: Find the GCD of the numerator and denominator.Step 2: Divide the numerator by GCD and store as the new numerator.Step 3: Divide the denominator by GCD and store as the new denominator.Static FunctionsRecall that static functions are class functions and not associated with instances of theclass (objects). In this class, the static functions GCD and LCM should accept inputsany input pair (a and b) and return an answer based upon that input pair. As such, thesefunctions can be used by the programmer upon Rational Number objects or randomvalues for a and b.Use the following main function to test your program. (have to use this main function)int main() {}cout << endl;// test constructors, accessors, mutatorscout << "Default Constructor: ";RatNum r1;cout << r1.getNum() << "/" << r1.getDen() << endl;cout << "Single Parameter Constructor: ";RatNum r2(2);cout << r2.getNum() << "/" << r2.getDen() << endl;cout << "Dual Parameter Constructor: ";RatNum r3(1,3);cout << r3.getNum() << "/" << r3.getDen() << endl;cout << "Accessors / Mutators: ";r3.setNum(3);r3.setDen(12);cout << r3.getNum() << "/" << r3.getDen() << endl;// test gcdcout << "\nGCD of the last fraction: "<< RatNum::gcd(r3.getNum(),r3.getDen()) << endl;cout << "GCD of 40 and 24: " << RatNum::gcd(40,24) << endl;// test lcmcout << "\nLCM of the last fraction:<< RatNum::lcm (r3.getNum(),r3.getDen()) << endl;cout << "LCM of 3 and 5: " << RatNum::lcm (3,5) << endl;11// test reducecout << "\nReducing the last fraction: ";r3.reduce();cout << r3.getNum() << "/" << r3.getDen() << endl;cout << endl;return 0;

A C++ program for the given criteria is as follows, File name: “main.cpp” #include <iostream>…

Output Example Default Constructor: 0/1 Single Parameter Constructor: 2/1 Dual Parameter Constructor: 1/3 Accessors / Mutators: 3/12 GCD of the last fraction: 3 GCD of 40 and 24: 8 LCM of the last fraction: 12 LCM of 3 and 5: 15 Reducing the last fraction: 1/4

Output Example Default Constructor: 0/1 Single Parameter Constructor: 2/1 Dual Parameter Constructor: 1/3 Accessors / Mutators: 3/12 GCD of the last fraction: 3 GCD of 40 and 24: 8 LCM of the last fraction: 12 LCM of 3 and 5: 15 Reducing the last fraction: 1/4

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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