I need help finding the force on a flat door at the bottom of the vessel that has a cross-sectional area of 0.5 m2. A vat contains a mixture of oil and water. The water forms a lower layer which is 0.8 m deep, and above it there is an oil layer 0.3 m thick. Thedensity of water is 1000 kg/m?, and the density of oil is 800 kg/m?.Find the force on a flat door at the bottom of the vessel that has a cross-sectional area of 0.5 m2.The acceleration due to gravity is 9.81 m/s?.Oil, P. = 800 kg/m3h. = 0.3 m%3D%3DWater,Pw= 1000 kg/m3hw = 0.8 mA = 0.5 m2O a.4.32 kNO b. 10.2 kNO c.1.28 kNOd.5.1 kNO .5.4 kN

Name: I need help finding the force on a flat door at the bottom of the vess
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Description: I need help finding the force on a flat door at the bottom of the vessel that has a cross-sectional area of 0.5 m2. A vat contains a mixture of oil and water. The water forms a lower layer which is 0.8 m deep, and above it there is an oil layer 0.3 m

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Answered: Oil, P. = 800 kg/m3 h. = 0.3 m Water,…

Engineering

Mechanical Engineering

Oil, P. = 800 kg/m3 h. = 0.3 m Water, Pw= 1000 kg/m3 %3D hw = 0.8 m A = 0.5 m2 7/////// kN

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter8: Centroids And Distributed Loads

Section: Chapter Questions

Problem 8.90P: The hemispherical glass bowl is filled with water. Find the location y of the center of gravity of...

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