How do I calculate this circuit? 8.3 mAand i HorwSulay mealculate the value of load power7 mA ISTI own doinW4doidWidde of values for this circuit:VIRPR₁+15 VJR Σ 18 ΚΩ27.1K2W18 ΚΩ<R2 Σ 9.1 kΩ R, ≥ 5.5 ΚΩMIR₂R312.74 TSV9.1 ΚΩWHIof values for this circuit:5.5 ΚΩ9100550014600Total1SV1.4 mA10.2kk21 Wpo10.2

Answered: Image /qna-images/answer/52b10830-a2c3-48c3-b361-4f5305907103.jpg

of values for this circuit: R₁ +15 V J R, Σ 18 kΩ ΚΩ 27.1K2) V I R 18 ΚΩ R₂9.1 kn R₂ 5.5 kn ΚΩ R₂ R3 12.74 TSV 9.1 ΚΩ I values for this circuit: 5.5 ΚΩ 9100 5500 209hi Total 15V 1.4 mA 10.2kk 21 w OPO 10.2

of values for this circuit: R₁ +15 V J R, Σ 18 kΩ ΚΩ 27.1K2) V I R 18 ΚΩ R₂9.1 kn R₂ 5.5 kn ΚΩ R₂ R3 12.74 TSV 9.1 ΚΩ I values for this circuit: 5.5 ΚΩ 9100 5500 209hi Total 15V 1.4 mA 10.2kk 21 w OPO 10.2

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter7: Alternating Current, Power Distribution, And Voltage Systems

Section: Chapter Questions

Problem 7RQ

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Concept explainers

HVDC

HVDC stands for high voltage direct current in the electric power transmission system. The high voltage direct current system uses direct current (DC) for the transmission of electrical power through transmission lines in contrast with the alternating current that is the AC system. The HVDC is used to transmit bulk power point-to-point through long distances transmission lines. Power is rapidly transferred because the efficiency of transmission lines is greatly increased over long distances due to HVDC lines.

Question

How do I calculate this circuit?

8.3 mA
and i Horw
Sulay me
alculate the value of load power
7 mA ISTI own doinW4
doidWid
d
e of values for this circuit:
V
I
R
P
R₁
+15 V
J
R Σ 18 ΚΩ
27.1K2
W
18 ΚΩ
<
R2 Σ 9.1 kΩ R, ≥ 5.5 ΚΩ
MI
R₂
R3
12.74 TSV
9.1 ΚΩ
WHI
of values for this circuit:
5.5 ΚΩ
9100
5500
14600
Total
1SV
1.4 mA
10.2kk
21 W
po
10.2

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