Now that you know the moles of NaOH used for each trial as well as the volume of NaOH used for each trial, calculate the concentration of the NaOH that you made in lab for each trial. Round to the ten-thousandths place please. Trial 1Trial 2Mass of KHP used0.16 KHP0.18 KHPInitial Buret readingfor your NaOH0.00 mL7.46 mLFinal Buret reading for7.46mL15.70mLyour NaOHTotal volume of NaOH7.46-0.00=15.70-7.46=used in titration7.46mL used8.24mL used

Chemical equation for the reaction of NaOH with KHP is: NaOH+KHP→NaKP+H2O 1 mole of NaOH is required…

Now that you know the moles of NaOH used for each trial as well as the volume of NaOH used for each trial, calculate the concentration of the NaOH that you made in lab for each trial. Round to the ten-thousandths place please.

Now that you know the moles of NaOH used for each trial as well as the volume of NaOH used for each trial, calculate the concentration of the NaOH that you made in lab for each trial. Round to the ten-thousandths place please.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter15: Complex Acid/base Systems

Section: Chapter Questions

Problem 15.29QAP

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Question

Trial 1
Trial 2
Mass of KHP used
0.16 KHP
0.18 KHP
Initial Buret reading
for your NaOH
0.00 mL
7.46 mL
Final Buret reading for
7.46mL
15.70mL
your NaOH
Total volume of NaOH
7.46-0.00=
15.70-7.46=
used in titration
7.46mL used
8.24mL used

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